Session Timeout AJAX Error in Tapestry Application
Asked Answered
M

3

7

I'm building a webapp using Tapestry in combination with Spring Security and the jQuery-library besides Prototype. When a user clicks on a link after his session timed out, he is automatically redirected to the login page. This, of course, does not work for links, that trigger an AJAX-request.

I know, this is a common problem with any kind of web application (e.g. http://www.openjs.com/articles/ajax/session_timeout.php). Is there a best practice solution for Tapestry 5?

EDIT The following solution (thanks to Henning) works for me:

Ajax.Responders.register(
{
    onException: function()
    {
        window.location.reload();
    }
});

In case of a failure during an AJAX-call a page reload is triggered, which in result redirects to the login-page. It still needs some tuning (e.g. display an error message instead of redirect), but using Ajax.Responders basically seems a good way to do it.

Moriahmoriarty answered 17/9, 2010 at 7:1 Comment(2)
do what the author suggest in the article. encounter it from javascript.Seek
Just reloading the page is a very elegant solution; I'll make that the new default for my apps. Thanks!Koniology
K
5

For the AJAX that uses Prototype, you could add a global listener that reacts to AJAX failures using AJAX.Responders; jQuery has a similar construct called Ajax Events that you could use.

Both event handlers should just redirect to the login page on a 403 error. You could create a mixin with this functionality and add it to your layout component.

I have also used a mechanism that prevents session timeouts while the app is still open in a browser window by just doing an AJAX call and receiving an empty response every couple of minutes, thus keeping the session open. Stupid, but works okay.

Koniology answered 17/9, 2010 at 7:25 Comment(0)
S
3

you can contribute the T5 master dispatcher


public class AjaxAccessController implements Dispatcher {

    @Override
    public boolean dispatch(Request request, Response response) throws IOException {

        // Si no hay session y la petición es ajax, recargar la página
        Session session = request.getSession(false);
        if (session == null && request.isXHR()) {
            OutputStream os = response.getOutputStream("application/json;charset=UTF-8");
            os.write("{\"script\":\"window.location.reload();\"}".getBytes());
            os.flush();
            return true;
        }

        return false;
    }
}

In your AppModule.java


public static void bind(ServiceBinder binder) {
        // binder.bind(MyServiceInterface.class, MyServiceImpl.class);
        // Make bind() calls on the binder object to define most IoC services.
        // Use service builder methods (example below) when the implementation
        // is provided inline, or requires more initialization than simply
        // invoking the constructor.

        // Id de AjaxAccessController
        binder.bind(AjaxAccessController.class).withId("AjaxAccessController");
    }

public void contributeMasterDispatcher(
            OrderedConfiguration configuration,
            @InjectService("AjaxAccessController") Dispatcher accessController) {

        configuration.add("AjaxAccessController", accessController, "before:ComponentEvent");
    }

So every ajax request without session, the page will reloads and it redirects to your index page

Sludgy answered 8/10, 2010 at 10:12 Comment(1)
This did not work for me on Tapestry 5.3.7. Instead I used a ComponentRequestFilter to do what u did in the Dispatcher.Negligent
A
0

Well, Ajax request is made to server it sends the header "HTTP_X_REQUESTED_WITH" with value "XMLHttpRequest". You can just check serverside that whether it is ajax request with above header and condition for login and session timeout before proceeding further in your index page.

If your criteria gets matched then simply print "window.top.location.href='login page'" in your function.

In PHP i can do this as ,

<?php if($_SERVER['HTTP_X_REQUESTED_WITH'] === "XMLHttpRequest" && condition for session check){
    echo "<script>window.top.location.href='login.php'</script>";
    }

?>

You can add the condition similar to it in your framework.

Apperceive answered 17/9, 2010 at 7:31 Comment(0)

© 2022 - 2024 — McMap. All rights reserved.