UIApplicationLaunchOptionsShortcutItemKey not there in Swift 3?

Question

Recently in Xcode 8 beta 6 (8S201h), this has become a problem.

 UIApplicationLaunchOptionsShortcutItemKey

Here's the error :

Anyone else having this issue?

var performShortcutDelegate = true
if let shortcutItem = launchOptions[UIApplicationLaunchOptionsKey.shortcutItem] as? UIApplicationShortcutItem {
    print("ok")
    self.shortcutItem = shortcutItem
    performShortcutDelegate = false
}
return performShortcutDelegate

Contaminant

Try using guard : #33690433 – Archive

no luck :( same error – Contaminant

So you're still getting the ambiguous reference to member subscript error? Your code looks correct as shown, so it might have something to do with the enclosing function. It's also possible you need to include the block if #available(iOS 9.0, *) {} around your shortcut code. More information/context would be helpful. :) – Doloritas

So I just realized you're not unwrapping launchOptions, meaning it's still of Optional type when you try to use it. You can't pull values from an Optional dictionary, because it's not technically a dictionary. That's likely the issue. I've updated my answer to reflect this, and included the enclosing function as well. Let me know if it works! – Doloritas

this still isn't working with Xcode 8 GM – Protect

Answer 1

The constant has changed (see the documentation). You also need to unwrap launchOptions before using any values it contains.

Enclosing function is included for context.

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
    if let launchOptions = launchOptions {
        if #available(iOS 9.0, *) {
            if let shortcutItem = launchOptions[UIApplicationLaunchOptionsKey.shortcutItem] as? UIApplicationShortcutItem {
                print("Shortcut: \(shortcutItem)")
            }
        }
    }
    return true
}

Doloritas

If this is in application(_:willFinishLaunchingWithOptions:), then the launchOptions dictionary is already known to have key type UIApplicationLaunchOptionsKey. So you can just use launchOptions[.shortcutItem]. – Phagocytosis

Can you update your question to include the code and the function it's inside? (Ideally, please paste it as inline code, not as a screenshot.) – Doloritas

My problem was the migration tool who missed changing the launchOptions type. So basically check the UIApplicationDelegate for the correct method interface. Should be launchOptions: [UIApplicationLaunchOptionsKey : Any]? = nil. – Landed

Answer 2

The launchOptions Dictionary type has changed in the function parameters to [UIApplicationLaunchOptionsKey: AnyObject].

private func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: AnyObject]?) -> Bool {

    ...

}

Protect

Answer 3

Try this.. Its work for me using Xcode8 , swift3

    //Check for ShortCutItem
    if #available(iOS 9.0, *) {
        if let shortcutItem = launchOptions?[UIApplicationLaunchOptionsKey.shortcutItem] as? UIApplicationShortcutItem {
        }
    }

Evita