So:
One-to-one: you could use a Dense
layer as you are not processing sequences:
model.add(Dense(output_size, input_shape=input_shape))
One-to-many: this option is not supported well as chaining models is not very easy in Keras
, so the following version is the easiest one:
model.add(RepeatVector(number_of_times, input_shape=input_shape))
model.add(LSTM(output_size, return_sequences=True))
Many-to-one: actually, your code snippet is (almost) an example of this approach:
model = Sequential()
model.add(LSTM(1, input_shape=(timesteps, data_dim)))
Many-to-many: This is the easiest snippet when the length of the input and output matches the number of recurrent steps:
model = Sequential()
model.add(LSTM(1, input_shape=(timesteps, data_dim), return_sequences=True))
Many-to-many when number of steps differ from input/output length: this is freaky hard in Keras. There are no easy code snippets to code that.
EDIT: Ad 5
In one of my recent applications, we implemented something which might be similar to many-to-many from the 4th image. In case you want to have a network with the following architecture (when an input is longer than the output):
O O O
| | |
O O O O O O
| | | | | |
O O O O O O
You could achieve this in the following manner:
model = Sequential()
model.add(LSTM(1, input_shape=(timesteps, data_dim), return_sequences=True))
model.add(Lambda(lambda x: x[:, -N:, :])) #Select last N from output
Where N
is the number of last steps you want to cover (on image N = 3
).
From this point getting to:
O O O
| | |
O O O O O O
| | |
O O O
is as simple as artificial padding sequence of length N
using e.g. with 0
vectors, in order to adjust it to an appropriate size.