How to convert View Model into JSON object in ASP.NET MVC?

Question

I am a Java developer, new to .NET. I am working on a .NET MVC2 project where I want to have a partial view to wrap a widget. Each JavaScript widget object has a JSON data object that would be populated by the model data. Then methods to update this data are bound to events when data is changed in the widget or if that data is changed in another widget.

The code is something like this:

MyController:

virtual public ActionResult DisplaySomeWidget(int id) {
  SomeModelView returnData = someDataMapper.getbyid(1);

  return View(myview, returnData);
}

myview.ascx:

<%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<SomeModelView>" %>

<script type="text/javascript">
  //creates base widget object;
  var thisWidgetName = new Widget();

  thisWidgetName.updateTable = function() {
    //  UpdatesData
  };
  $(document).ready(function () {
    thisWidgetName.data = <% converttoJSON(model) %>
    $(document).bind('DATA_CHANGED', thisWidgetName.updateTable());
  });
</script>

<div><%:model.name%></div>

What I don’t know is how to send the data over as SomeModelView and then be able to use that to populate the widget as well as convert that to JSON. I had seen some real simple ways to do it in the controller but not in the view. I figure this is a basic question but I’ve been going for a few hours trying to make this slick.

Popover

I know this is an old question. But as of today there are better ways to do it. Don't mix JSON inline with your View result. JSON is easily seriales via AJAX and can be treated like objects. Anything in JavaScript should be separate from the View. You can easily return models without any effort via a Controller. – Walkin

@PiotrKula Sometimes order of initialization suggests a preference regarding where JavaScript is included and assigned. There is always a level of effort, but it sometimes differs in amount depending on where it's placed. Inline JavaScript declarations and initializations are acceptable in a View to avoid inconvenience and greater effort. – Berte

Answer 1

In mvc3 with razor @Html.Raw(Json.Encode(object)) seems to do the trick.

Zymo

+1 I used Html.Raw, but never found Json.Encode and just used JavaScriptSerializer to add the string in the controller to the view model – Cns

That works like a charm. I think it works better in the view in certain instances. – Casady

This approach works even when you want to pass the resulting JSON to Javascript. Razor complains with the green squiggles if you put the @Html.Raw(...) code as a function parameter inside <script> tags, but the JSON does indeed make it to the JS being called. Very handy & slick. +1 – Lutyens

This is the way to do it since MVC3 and should be returned from a controller. Don't embed json into your Viewresult. Instead make a controller to handle the JSON separately and do a JSON request via AJAX. If you need JSON on the view you are doing something wrong. Either use a ViewModel or something else. – Walkin

Does Json.Encode do the same thing as Newtonsoft.Json.JsonConvert.SerializeObject? – Calabar

It even works on ASP.NET MVC 5. But don't forget to add [ScriptIgnore] on virtual properties to avoid circular reference. – Apograph

Json.Encode can be found in System.Web.Helpers which seems to come with the .NET framework 4 – Headline

Json.Encode encodes my 2-dimensional array to a 1-dimensional array in json. Newtonsoft.Json.JsonConvert.SerializeObject serializes the two dimensions properly into json. So I suggest to use the latter one. – Phosphate

When using MVC 6 (maybe also 5) you need to use Json.Serialize instead of Encode. – Hexapody

Adapted to: <pre>@Html.Raw(Newtonsoft.Json.JsonConvert.SerializeObject(Model, Newtonsoft.Json.Formatting.Indented))</pre> – Pinnatifid

For some reason Json.Serialize changes my property names from Pascal case to camelCase – Zymo

If i do var json = @Html.Raw(Json.Encode(Model.x)) and alert(json[i])....it just returns [Object object] how can i access a property of my Model element – Fantasy

What is namespace for Json.Serialize ? – Magdalenamagdalene

Answer 2

Well done, you've only just started using MVC and you've found its first major flaw.

You don't really want to be converting it to JSON in the view, and you don't really want to convert it in the controller, as neither of these locations make sense. Unfortunately, you're stuck with this situation.

The best thing I've found to do is send the JSON to the view in a ViewModel, like this:

var data = somedata;
var viewModel = new ViewModel();
var serializer = new JavaScriptSerializer();
viewModel.JsonData = serializer.Serialize(data);

return View("viewname", viewModel);

then use

<%= Model.JsonData %>

in your view. Be aware that the standard .NET JavaScriptSerializer is pretty crap.

doing it in the controller at least makes it testable (although not exactly like the above - you probably want to take an ISerializer as a dependency so you can mock it)

Update also, regarding your JavaScript, it would be good practice to wrap ALL the widget JS you have above like so:

(
    // all js here
)();

this way if you put multiple widgets on a page, you won't get conflicts (unless you need to access the methods from elsewhere in the page, but in that case you should be registering the widget with some widget framework anyway). It may not be a problem now, but it would be good practice to add the brackets now to save yourself muchos effort in the future when it becomes a requirement, it's also good OO practice to encapsulate the functionality.

Nette

This looks interesting. I was going to just make a copy of the data as json and pass it as viewData but this way it looks more interesting. I'll play with this and let you know. BTW this is my first time posting a question on stackoverflow and it took what..5 minutes to get good responses, that is awesome!! – Popover

nothings wrong with it, its just not customisable, if you want any custom value formatting you have to do it before hand, basically making everything a string :( this is most prominent with dates. i know there are easy workarounds, but they shouldnt be necessary! – Nette

@Update I was going see about using a .net static counter of that widget to generate a unique object name. But what you wrote looks like it would accomplish the same thing and do it slicker. Also I did look into binding the creation of a widget "new_widget_event' to a page level object to track them but the original reason for doing that became OBE. So I might revisit that later. thanks for all the help I'm going to post a modified version of what you suggested but put explain why I like it better. – Popover

i retract my previous statement "theres nothing wrong with it". There's everything wrong with it. – Nette

Why do you say that we can't return JSON from the controller. That is how its supposed to be done. Using JavaScriptSerializer or Return Json(object) both use the same serializers. Also posting the same JSON back to the controller will rebuild the object for you as long as you define the correct model. Maybe during MVC2 it was a major drawback.. but today its a breeze and very convenient. You should update your answer to reflect this. – Walkin

The biggest problem with JsonHelper, as Andrew said, is it's not customizable. Want camelCase properties? Too bad. Roll your own JsonHelper and let it be often confused with the JsonHelper that you can't hide. – Arboretum

is there a way back from json object to create original model object ? – Magdalenamagdalene

Answer 3

I found it to be pretty nice to do it like this (usage in the view):

    @Html.HiddenJsonFor(m => m.TrackingTypes)

Here is the according helper method Extension class:

public static class DataHelpers
{
    public static MvcHtmlString HiddenJsonFor<TModel, TProperty>(this HtmlHelper<TModel> htmlHelper, Expression<Func<TModel, TProperty>> expression)
    {
        return HiddenJsonFor(htmlHelper, expression, (IDictionary<string, object>) null);
    }

    public static MvcHtmlString HiddenJsonFor<TModel, TProperty>(this HtmlHelper<TModel> htmlHelper, Expression<Func<TModel, TProperty>> expression, object htmlAttributes)
    {
        return HiddenJsonFor(htmlHelper, expression, HtmlHelper.AnonymousObjectToHtmlAttributes(htmlAttributes));
    }

    public static MvcHtmlString HiddenJsonFor<TModel, TProperty>(this HtmlHelper<TModel> htmlHelper, Expression<Func<TModel, TProperty>> expression, IDictionary<string, object> htmlAttributes)
    {
        var name = ExpressionHelper.GetExpressionText(expression);
        var metadata = ModelMetadata.FromLambdaExpression(expression, htmlHelper.ViewData);

        var tagBuilder = new TagBuilder("input");
        tagBuilder.MergeAttributes(htmlAttributes);
        tagBuilder.MergeAttribute("name", name);
        tagBuilder.MergeAttribute("type", "hidden");

        var json = JsonConvert.SerializeObject(metadata.Model);

        tagBuilder.MergeAttribute("value", json);

        return MvcHtmlString.Create(tagBuilder.ToString());
    }
}

It is not super-sofisticated, but it solves the problem of where to put it (in Controller or in view?) The answer is obviously: neither ;)

Kalmia

This was nice and clean in my opinion and wrapped up in a reusable helper. Cheers, J – Urger

Answer 4

You can use Json from the action directly,

Your action would be something like this:

virtual public JsonResult DisplaySomeWidget(int id)
{
    SomeModelView returnData = someDataMapper.getbyid(id);
    return Json(returnData);
}

Edit

Just saw that you assume this is the Model of a View so the above isn't strictly correct, you would have to make an Ajax call to the controller method to get this, the ascx would not then have a model per se, I will leave my code in just in case it is useful to you and you can amend the call

Edit 2 just put id into the code

Henslowe

but he cant render this into the view, he'd have to make a 2nd ajax call – Nette

Thanks, I was originally doing this using a jQuery get json call and was planning on having the HTML elements populate them selves from json. However, the pattern we are following right now is that our views should return a modelView and that is the easiest way to populate basic HTML elements like tables etc. I could send over the same data in JSON format as ViewData but it seems wasteful. – Popover

YOu should NOT be embedding JSON with a View Result. The OP either needs to stick to standard MVC practised and return a model or viewmodel or do an AJAX. There is absolutely NO REASON to embed JSON with a view. That is just very dirty code. This answer is the correct way and the recommended way by Microsoft Practices. The downvote was unnecessary this is definitely the correct answer. We should not encourage bad coding practices. Either JSON via AJAX or Models via Views. Nobody likes spaghetti code with mixed markup! – Walkin

This solution will result in the following problem: #10544453 – Fructidor

Answer 5

@Html.Raw(Json.Encode(object)) can be used to convert the View Modal Object to JSON

Spacial

Answer 6

Extending the great answer from Dave. You can create a simple HtmlHelper.

public static IHtmlString RenderAsJson(this HtmlHelper helper, object model)
{
    return helper.Raw(Json.Encode(model));
}

And in your view:

@Html.RenderAsJson(Model)

This way you can centralize the logic for creating the JSON if you, for some reason, would like to change the logic later.

Unashamed

Answer 7

For ASP.NET Core 3.1 and later versions you can use System.Text.Json namespace to serialize ViewModel to JSON:

@using System.Text.Json

...

@section Scripts {
    <script>
        const model = @Html.Raw(JsonSerializer.Serialize(Model));
    </script>
}

Marked

Answer 8

Andrew had a great response but I wanted to tweek it a little. The way this is different is that I like my ModelViews to not have overhead data in them. Just the data for the object. It seem that ViewData fits the bill for over head data, but of course I'm new at this. I suggest doing something like this.

Controller

virtual public ActionResult DisplaySomeWidget(int id)
{
    SomeModelView returnData = someDataMapper.getbyid(1);
    var serializer = new JavaScriptSerializer();
    ViewData["JSON"] = serializer.Serialize(returnData);
    return View(myview, returnData);
}

View

//create base js object;
var myWidget= new Widget(); //Widget is a class with a public member variable called data.
myWidget.data= <%= ViewData["JSON"] %>;

What This does for you is it gives you the same data in your JSON as in your ModelView so you can potentially return the JSON back to your controller and it would have all the parts. This is similar to just requesting it via a JSONRequest however it requires one less call so it saves you that overhead. BTW this is funky for Dates but that seems like another thread.

Popover

Answer 9

<htmltag id=’elementId’ data-ZZZZ’=’@Html.Raw(Json.Encode(Model))’ />

Refer https://highspeedlowdrag.wordpress.com/2014/08/23/mvc-data-to-jquery-data/

I did below and it works like charm.

<input id="hdnElement" class="hdnElement" type="hidden" value='@Html.Raw(Json.Encode(Model))'>

Rondelet