How can I skip first several lines of the Excel sheet?

Question

Using openpyxl I tried to read from the fifth line for some files. The files' first four lines are the header. Then the main content has a different format from the header. And I tried the method:

import openpyxl
file_name="xxx.xlsx"
wb = openpyxl.load_workbook(filename=file_name, use_iterators = True)
first_sheet = workbook.get_sheet_names()[0]
ws = workbook.get_sheet_by_name(first_sheet)

for index, row in enumerate(ws.iter_rows()):
    if start < index < stop:
        for c in row:
           print c.value

It will always have the error:

IndexError: list index out of range

If I delete the first four lines, the data can be read into Python easily. But I have hundreds of such files, each file has a header for four lines. It will take way much time to delete all the headers from the files.

How to skip first several lines when reading using openpyxl correctly?

Milkwort

Answer 1

You can skip the first N rows by passing the optional min_row argument. Note that this uses a 1-base index, so min_row=2 starts on the second row and min_row=5 skips the first four rows. You would be using something like this:

for index, row in enumerate(ws.iter_rows(min_row=5)):

Full iter_rows documentation.

Tiertza

Answer 2

You can pass a range into ws.iter_rows('A4:Z256') but you're probably better off using ws.get_squared_range(1, 5,)

Sarcophagus