Bash: Sort files from 'find' by contents

Question

I have the line:

find -maxdepth 1 -type f -iname '*key*'  -not -name '*~'

I want to extract the contents (which should be text) of all the files returned and pipe that into sort to be sorted alphabetically. I've tried piping the output of the above line directly into sort but this results in the file names being sorted rather than their contents. Do I need to turn the output of find into an array and then have it processed by sort?

[edit] The output I want is the sorted contents.

Brian

Pipe it through xargs cat then through sort. – Champion

Answer 1

For completeness sake here are a few more ways of doing that:

1. find -maxdepth 1 -type f -iname '*key*' -not -name '*~' -exec cat {} \; | sort
2. find -maxdepth 1 -type f -iname '*key*' -not -name '*~' | xargs cat | sort
3. cat $(find -maxdepth 1 -type f -iname '*key*' -not -name '*~') | sort

Champion

Answer 2

If you would like to save the sorted output into a file, try:

find -maxdepth 1 -type f -iname '*key*'  -not -name '*~' | cat | sort > sorted.txt

otherwise just get rid of > sorted.txt and the sorted output will be printed to the terminal window.

Charged