I'm trying to figure out a way to set permissions recursively 700 for dirs and subdirs on a specific path and 600 for files. I would use these commands:
find /path -type d -print0 | xargs -0 chmod 700
find /path -type f -print0 | xargs -0 chmod 600
But the user does not have permission to run the "find" command. As a workaround I tried to make a script that contains the above commands from the root user with setuid sticky bit set so it will run with root privileges (like passwd or sudo commands that normal users run with root privileges):
chmod 4755 script.sh
but i cannot execute the script from the limited user account, it still says that I don't have permission to run the find command.
Does anyone have any idea how i can accomplish this without having to use the find
command?
Edit: OS: Centos 6.5
chmod
version doesn't quite work properly, theX
is a special execute that will grant execute permissions if at least one of the other modes has execute. That means if the file already hadx
in user group or other, then it will remain with an execute setting on the user. To do this with only chmod, we must first wipe out all execute settings in the beginning, then run your chmod command. For examplechmod -R a-x /path; chmod -R u=rwX,g=,o= /path
. – Formicary