Just for fun, here's one way to use generics in order to redim/extend a unidimensional array (add one more "row") :
static T[] Redim<T>(T[] arr, bool preserved)
{
int arrLength = arr.Length;
T[] arrRedimed = new T[arrLength + 1];
if (preserved)
{
for (int i = 0; i < arrLength; i++)
{
arrRedimed[i] = arr[i];
}
}
return arrRedimed;
}
And one to add n rows (though this doesn't prevent user from undersizing the array, which will throw an error in the for loop) :
static T[] Redim<T>(T[] arr, bool preserved, int nbRows)
{
T[] arrRedimed = new T[nbRows];
if (preserved)
{
for (int i = 0; i < arr.Length; i++)
{
arrRedimed[i] = arr[i];
}
}
return arrRedimed;
}
I'm sure you get the idea.
For a multidimensional array (two dimensions), here's one possibility:
static T[,] Redim<T>(T[,] arr, bool preserved)
{
int Ubound0 = arr.GetUpperBound(0);
int Ubound1 = arr.GetUpperBound(1);
T[,] arrRedimed = new T[Ubound0 + 1, Ubound1];
if (preserved)
{
for (int j = 0; j < Ubound1; j++)
{
for (int i = 0; i < Ubound0; i++)
{
arrRedimed[i, j] = arr[i, j];
}
}
}
return arrRedimed;
}
In your program, use this with or even without the type specified, the compiler will recognize it :
int[] myArr = new int[10];
myArr = Redim<int>(myArr, true);
or
int[] myArr = new int[10];
myArr = Redim(myArr, true);
Not sure if all this is really relevant though. =D
Please feel free to correct me or improve my code. ;)