closest() method not working as expected
Asked Answered
G

1

7

I've a sample example below, I'm not sure why the first example (using div's) didn't get the text when the second one (using span's) could achieve that with the same JS code using closest():

$('.class-1').closest('div').find('.class-2').text()

First snippet (using div's) cant get the text using closest():

console.log( $('.class-1').closest('div').find('.class-2').text() );
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
  <div class="class-1">Div 1 Content</div>
  <div class="class-2">Div 2 Content</div>
</div>

Second snippet (using span's) getting the text using closest():

console.log( $('.class-1').closest('div').find('.class-2').text() );
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
  <span class="class-1">Div 1 Content</span>
  <br/>
  <span class="class-2">Div 2 Content</span>
</div>

I know about the alternatives parents()/parent()/siblings()/nextAll() that can return the class-2 text in this case, but I want just to know what occur this behaviour.

Guggle answered 6/1, 2017 at 14:41 Comment(1)
It's because closest() includes the current element, therefore closest('div') is returning the same element. See api.jquery.com/closestTails
D
13

Because .closest() checks if the calling element fits the selector as well, and in your case .class-1 is also a div.

From the docs:

Description: For each element in the set, get the first element that matches the selector by testing the element itself and traversing up through its ancestors in the DOM tree.

Dispensatory answered 6/1, 2017 at 14:43 Comment(0)

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