0 is a falsy value, so when it is evaluated by &&, it returns 0. However, 0 is renderable by React because it is a number:
// Renderable values
1 && <GeneralLoader /> // => Renders <GeneralLoader />
"a string" && <GeneralLoader /> // => Renders <GeneralLoader />
0 && <GeneralLoader /> // => Renders '0'
// Non-renderable values
false && <GeneralLoader /> // => Renders nothing
null && <GeneralLoader /> // => Renders nothing
undefined && <GeneralLoader /> // => Renders nothing
TLDR
This is because of how javascript itself process [truthy and falsy values][1]:
In JavaScript, a truthy value is a value that is considered true when
encountered in a Boolean context. All values are truthy unless they
are defined as falsy (i.e., except for false, 0, "", null, undefined,
and NaN).
When used with the && operator, the returned value depends on the left value:
- If the left value is truthy, the right value is returned.
- If the left value is falsy, its value is returned.
Examples:
// Truthy values
1 && "hello" // => "hello"
"a string" && "hello" // => "hello"
// Falsy values
0 && "hello" // => 0
false && "hello" // => false
null && "hello" // => null
undefined && "hello" // => undefined
The same rules applies to JSX because it is [a syntax extension to JavaScript][2]. However, the issue is that **
The issue is that 0 is a falsy value, so when it is evaluated by &&, it returns 0. However, 0 is renderable by React because it is a number
// Renderable values
1 && <GeneralLoader /> // => Renders <GeneralLoader />
"a string" && <GeneralLoader /> // => Renders <GeneralLoader />
0 && <GeneralLoader /> // => Renders 0
// Non-renderable values
false && <GeneralLoader /> // => Renders nothing
null && <GeneralLoader /> // => Renders nothing
undefined && <GeneralLoader /> // => Renders nothing