How to parse freeform street/postal address out of text, and into components
Asked Answered
E

6

173

We do business largely in the United States and are trying to improve user experience by combining all the address fields into a single text area. But there are a few problems:

  • The address the user types may not be correct or in a standard format
  • The address must be separated into parts (street, city, state, etc.) to process credit card payments
  • Users may enter more than just their address (like their name or company with it)
  • Google can do this but the Terms of Service and query limits are prohibitive, especially on a tight budget

Apparently, this is a common question:

Is there a way to isolate an address from the text around it and break it into pieces? Is there a regular expression to parse addresses?

Edlin answered 22/6, 2012 at 16:19 Comment(0)
E
336

I saw this question a lot when I worked for an address verification company. I'm posting the answer here to make it more accessible to programmers who are searching around with the same question. The company I was at processed billions of addresses, and we learned a lot in the process.

First, we need to understand a few things about addresses.

Addresses are not regular

This means that regular expressions are out. I've seen it all, from simple regular expressions that match addresses in a very specific format, to this:

/\s+(\d{2,5}\s+)(?![a|p]m\b)(([a-zA-Z|\s+]{1,5}){1,2})?([\s|,|.]+)?(([a-zA-Z|\s+]{1,30}){1,4})(court|ct|street|st|drive|dr|lane|ln|road|rd|blvd)([\s|,|.|;]+)?(([a-zA-Z|\s+]{1,30}){1,2})([\s|,|.]+)?\b(AK|AL|AR|AZ|CA|CO|CT|DC|DE|FL|GA|GU|HI|IA|ID|IL|IN|KS|KY|LA|MA|MD|ME|MI|MN|MO|MS|MT|NC|ND|NE|NH|NJ|NM|NV|NY|OH|OK|OR|PA|RI|SC|SD|TN|TX|UT|VA|VI|VT|WA|WI|WV|WY)([\s|,|.]+)?(\s+\d{5})?([\s|,|.]+)/i

... to this where a 900+ line-class file generates a supermassive regular expression on the fly to match even more. I don't recommend these (for example, here's a fiddle of the above regex, that makes plenty of mistakes). There isn't an easy magic formula to get this to work. In theory and by theory, it's not possible to match addresses with a regular expression.

USPS Publication 28 documents the many formats of addresses that are possible, with all their keywords and variations. Worst of all, addresses are often ambiguous. Words can mean more than one thing ("St" can be "Saint" or "Street") and there are words that I'm pretty sure they invented. (Who knew that "Stravenue" was a street suffix?)

You'd need some code that really understands addresses, and if that code does exist, it's a trade secret. But you could probably roll your own if you're really into that.

Addresses come in unexpected shapes and sizes

Here are some contrived (but complete) addresses:

1)  102 main street
    Anytown, state

2)  400n 600e #2, 52173

3)  p.o. #104 60203

Even these are possibly valid:

4)  829 LKSDFJlkjsdflkjsdljf Bkpw 12345

5)  205 1105 14 90210

Obviously, these are not standardized. Punctuation and line breaks not guaranteed. Here's what's going on:

  1. Number 1 is complete because it contains a street address and a city and state. With that information, there's enough to identify the address, and it can be considered "deliverable" (with some standardization).

  2. Number 2 is complete because it also contains a street address (with secondary/unit number) and a 5-digit ZIP code, which is enough to identify an address.

  3. Number 3 is a complete post office box format, as it contains a ZIP code.

  4. Number 4 is also complete because the ZIP code is unique, meaning that a private entity or corporation has purchased that address space. A unique ZIP code is for high-volume or concentrated delivery spaces. Anything addressed to ZIP code 12345 goes to General Electric in Schenectady, NY. This example won't reach anyone in particular, but the USPS would still be able to deliver it.

  5. Number 5 is also complete, believe it or not. With just those numbers, the full address can be discovered when parsed against a database of all possible addresses. Filling in the missing directionals, secondary designator, and ZIP+4 code is trivial when you see each number as a component. Here's what it looks like, fully expanded and standardized:

205 N 1105 W Apt 14

Beverly Hills CA 90210-5221

Address data is not your own

In most countries that provide official address data to licensed vendors, the address data itself belongs to the governing agency. In the US, the USPS owns the addresses. The same is true for Canada Post, Royal Mail, and others, though each country enforces or defines ownership a little differently. Knowing this is important, since it usually forbids reverse-engineering the address database. You have to be careful how to acquire, store, and use the data.

Google Maps is a common go-to for quick address fixes, but the TOS is rather prohibitive; for example, you can't use their data or APIs without showing a Google Map, and for non-commercial purposes only (unless you pay), and you can't store the data (except for temporary caching). Makes sense. Google's data is some of the best in the world. However, Google Maps does not verify the address. If an address does not exist, it will still show you where the address would be if it did exist (try it on your own street; use a house number that you know doesn't exist). This is useful sometimes, but be aware of that.

Nominatim's usage policy is similarly limiting, especially for high volume and commercial use, and the data is mostly drawn from free sources, so it isn't as well maintained (such is the nature of open projects) -- however, this may still suit your needs. It is supported by a great community.

The USPS itself has an API, but it goes down a lot and comes with no guarantees nor support. It might also be hard to use. Some people use it sparingly with no problems. But it's easy to miss that the USPS requires that you use their API only for confirming addresses to ship through them.

People expect addresses to be hard

Unfortunately, we've conditioned our society to expect addresses to be complicated. There's dozens of good UX articles all over the Internet about this, but the fact is, if you have an address form with individual fields, that's what users expect, even though it makes it harder for edge-case addresses that don't fit the format the form is expecting, or maybe the form requires a field it shouldn't. Or users don't know where to put a certain part of their address.

I could go on and on about the bad UX of checkout forms these days, but instead I'll just say that combining the addresses into a single field will be a welcome change -- people will be able to type their address how they see fit, rather than trying to figure out your lengthy form. However, this change will be unexpected and users may find it a little jarring at first. Just be aware of that.

Part of this pain can be alleviated by putting the country field out front, before the address. When they fill out the country field first, you know how to make your form appear. Maybe you have a good way to deal with single-field US addresses, so if they select United States, you can reduce your form to a single field, otherwise show the component fields. Just things to think about!

Now we know why it's hard; what can you do about it?

The USPS licenses vendors through a process called CASS™ Certification to provide verified addresses to customers. These vendors have access to the USPS database, updated monthly. Their software must conform to rigorous standards to be certified, and they don't often require agreement to such limiting terms as discussed above.

There are many CASS-Certified companies that can process lists or have APIs: Melissa Data, Experian QAS, and SmartyStreets to name a few.

(Due to getting flak for "advertising" I've truncated my answer at this point. It's up to you to find a solution that works for you.)

The Truth: Really, folks, I don't work at any of these companies. It's not an advertisement.

Edlin answered 22/6, 2012 at 16:19 Comment(6)
q: when you were working on CASS compliance... just guestimating by memory, how much of the code is algorithm based (anything from regex to ML) versus data driven (state/zip/road lookups)?Crenate
@ScottBrickey Hard to say. Here's the technical manual for implementing CASS-certified software. Ultimately they don't care how you do it as long as it passes the tests. It's very algorithm heavy, but there are also lots of data lookups.Edlin
@Edlin thanks... i've looked at their docs a few times... a lot of it appears to be the order of lookups (validate zip vs city/state)... sprinkled in with a bit of fuzzy text matching (levenshtein seems to be a common approach)... but I keep figuring that it can't be that direct and that I must be missing aspects.Crenate
your regex doesn't match with 205 N 1105 W Apt 14 Beverly Hills CA 90210-5221Moneyed
@KamalHussain He wasn't suggesting that the regex did work for all cases. Two sentences later he says: "I don't recommend these…"Montespan
I programmed assembler and C for a large demographic marketing/direct mailer through the early 90s and I remember how valuable were the capabilities to standardize/complete addresses and to qualify for discounts by precisely coding down to the carrier.Muliebrity
L
15

There are many street address parsers. They come in two basic flavors - ones that have databases of place names and street names, and ones that don't.

A regular expression street address parser can get up to about a 95% success rate without much trouble. Then you start hitting the unusual cases. The Perl one in CPAN, "Geo::StreetAddress::US", is about that good. There are Python and Javascript ports of that, all open source. I have an improved version in Python which moves the success rate up slightly by handling more cases. To get the last 3% right, though, you need databases to help with disambiguation.

A database with 3-digit ZIP codes and US state names and abbreviations is a big help. When a parser sees a consistent postal code and state name, it can start to lock on to the format. This works very well for the US and UK.

Proper street address parsing starts from the end and works backwards. That's how the USPS systems do it. Addresses are least ambiguous at the end, where country names, city names, and postal codes are relatively easy to recognize. Street names can usually be isolated. Locations on streets are the most complex to parse; there you encounter things such as "Fifth Floor" and "Staples Pavillion". That's when a database is a big help.

Locution answered 5/4, 2015 at 5:25 Comment(2)
There is also the CPAN module Lingua:EN::AddressParse. While slower than "Geo::StreetAddress::US, it gives a higher success rate.Bendigo
Could you recommend one without database for UK? thanks!Breastbone
F
10

UPDATE: Geocode.xyz now works worldwide. For examples see https://geocode.xyz

For USA, Mexico and Canada, see geocoder.ca.

For example:

Input: something going on near the intersection of main and arthur kill rd new york

Output:

<geodata>
  <latt>40.5123510000</latt>
  <longt>-74.2500500000</longt>
  <AreaCode>347,718</AreaCode>
  <TimeZone>America/New_York</TimeZone>
  <standard>
    <street1>main</street1>
    <street2>arthur kill</street2>
    <stnumber/>
    <staddress/>
    <city>STATEN ISLAND</city>
    <prov>NY</prov>
    <postal>11385</postal>
    <confidence>0.9</confidence>
  </standard>
</geodata>

You may also check the results in the web interface or get output as Json or Jsonp. eg. I'm looking for restaurants around 123 Main Street, New York

Fagen answered 22/12, 2015 at 0:41 Comment(5)
How you implemented the address parsing system using openaddress ? Are you using brute force strategy ?Sarmentose
What do you mean by 'brute force'? Breaking up text into all possible combinations of possible address strings and comparing each one against a database of addresses is not practical and will take way more time to provide an answer than this system does. Openaddresses are one of the data sources for building a 'training set' of address formats for the algorithm. It uses this information to parse addresses out of unstructured text.Fagen
Another similar system is Geo::libpostal ( perltricks.com/article/announcing-geo--libpostal ) They also use openstreetmap and openaddresses it seems, to build address templates on the flyFagen
I just tested geocode.xyz's geoparser (send in text, get back location) on hundreds of actual addresses. Given a side by side with google map's API, and a global set of addresses, geocode.xyz's scantext method failed most of the time. It always chose "Geneva,US" over "Geneva, Switzerland" and was generally US biased.Woollyheaded
It depends on the context. geocode.xyz/?scantext=Geneva,%20Switzerland will produce: Match Location Geneva, Switzerland, CH Confidence Score: 0.8 while geocode.xyz/?scantext=Geneva,%20USA will produce Match Location Geneva,US Confidence Score: 1.0 Also, you can region bias as follows: geocode.xyz/?scantext=Geneva,%20USA&region=CHFagen
P
5

No code? For shame!

Here is a simple JavaScript address parser. It's pretty awful for every single reason that Matt gives in his dissertation above (which I almost 100% agree with: addresses are complex types, and humans make mistakes; better to outsource and automate this - when you can afford to).

But rather than cry, I decided to try:

This code works OK for parsing most Esri results for findAddressCandidate and also with some other (reverse)geocoders that return single-line address where street/city/state are delimited by commas. You can extend if you want or write country-specific parsers. Or just use this as case study of how challenging this exercise can be or at how lousy I am at JavaScript. I admit I only spent about thirty mins on this (future iterations could add caches, zip validation, and state lookups as well as user location context), but it worked for my use case: End user sees form that parses geocode search response into 4 textboxes. If address parsing comes out wrong (which is rare unless source data was poor) it's no big deal - the user gets to verify and fix it! (But for automated solutions could either discard/ignore or flag as error so dev can either support the new format or fix source data.)

/* 
address assumptions:
- US addresses only (probably want separate parser for different countries)
- No country code expected.
- if last token is a number it is probably a postal code
-- 5 digit number means more likely
- if last token is a hyphenated string it might be a postal code
-- if both sides are numeric, and in form #####-#### it is more likely
- if city is supplied, state will also be supplied (city names not unique)
- zip/postal code may be omitted even if has city & state
- state may be two-char code or may be full state name.
- commas: 
-- last comma is usually city/state separator
-- second-to-last comma is possibly street/city separator
-- other commas are building-specific stuff that I don't care about right now.
- token count:
-- because units, street names, and city names may contain spaces token count highly variable.
-- simplest address has at least two tokens: 714 OAK
-- common simple address has at least four tokens: 714 S OAK ST
-- common full (mailing) address has at least 5-7:
--- 714 OAK, RUMTOWN, VA 59201
--- 714 S OAK ST, RUMTOWN, VA 59201
-- complex address may have a dozen or more:
--- MAGICICIAN SUPPLY, LLC, UNIT 213A, MAGIC TOWN MALL, 13 MAGIC CIRCLE DRIVE, LAND OF MAGIC, MA 73122-3412
*/

var rawtext = $("textarea").val();
var rawlist = rawtext.split("\n");

function ParseAddressEsri(singleLineaddressString) {
  var address = {
    street: "",
    city: "",
    state: "",
    postalCode: ""
  };

  // tokenize by space (retain commas in tokens)
  var tokens = singleLineaddressString.split(/[\s]+/);
  var tokenCount = tokens.length;
  var lastToken = tokens.pop();
  if (
    // if numeric assume postal code (ignore length, for now)
    !isNaN(lastToken) ||
    // if hyphenated assume long zip code, ignore whether numeric, for now
    lastToken.split("-").length - 1 === 1) {
    address.postalCode = lastToken;
    lastToken = tokens.pop();
  }

  if (lastToken && isNaN(lastToken)) {
    if (address.postalCode.length && lastToken.length === 2) {
      // assume state/province code ONLY if had postal code
      // otherwise it could be a simple address like "714 S OAK ST"
      // where "ST" for "street" looks like two-letter state code
      // possibly this could be resolved with registry of known state codes, but meh. (and may collide anyway)
      address.state = lastToken;
      lastToken = tokens.pop();
    }
    if (address.state.length === 0) {
      // check for special case: might have State name instead of State Code.
      var stateNameParts = [lastToken.endsWith(",") ? lastToken.substring(0, lastToken.length - 1) : lastToken];

      // check remaining tokens from right-to-left for the first comma
      while (2 + 2 != 5) {
        lastToken = tokens.pop();
        if (!lastToken) break;
        else if (lastToken.endsWith(",")) {
          // found separator, ignore stuff on left side
          tokens.push(lastToken); // put it back
          break;
        } else {
          stateNameParts.unshift(lastToken);
        }
      }
      address.state = stateNameParts.join(' ');
      lastToken = tokens.pop();
    }
  }

  if (lastToken) {
    // here is where it gets trickier:
    if (address.state.length) {
      // if there is a state, then assume there is also a city and street.
      // PROBLEM: city may be multiple words (spaces)
      // but we can pretty safely assume next-from-last token is at least PART of the city name
      // most cities are single-name. It would be very helpful if we knew more context, like
      // the name of the city user is in. But ignore that for now.
      // ideally would have zip code service or lookup to give city name for the zip code.
      var cityNameParts = [lastToken.endsWith(",") ? lastToken.substring(0, lastToken.length - 1) : lastToken];

      // assumption / RULE: street and city must have comma delimiter
      // addresses that do not follow this rule will be wrong only if city has space
      // but don't care because Esri formats put comma before City
      var streetNameParts = [];

      // check remaining tokens from right-to-left for the first comma
      while (2 + 2 != 5) {
        lastToken = tokens.pop();
        if (!lastToken) break;
        else if (lastToken.endsWith(",")) {
          // found end of street address (may include building, etc. - don't care right now)
          // add token back to end, but remove trailing comma (it did its job)
          tokens.push(lastToken.endsWith(",") ? lastToken.substring(0, lastToken.length - 1) : lastToken);
          streetNameParts = tokens;
          break;
        } else {
          cityNameParts.unshift(lastToken);
        }
      }
      address.city = cityNameParts.join(' ');
      address.street = streetNameParts.join(' ');
    } else {
      // if there is NO state, then assume there is NO city also, just street! (easy)
      // reasoning: city names are not very original (Portland, OR and Portland, ME) so if user wants city they need to store state also (but if you are only ever in Portlan, OR, you don't care about city/state)
      // put last token back in list, then rejoin on space
      tokens.push(lastToken);
      address.street = tokens.join(' ');
    }
  }
  // when parsing right-to-left hard to know if street only vs street + city/state
  // hack fix for now is to shift stuff around.
  // assumption/requirement: will always have at least street part; you will never just get "city, state"  
  // could possibly tweak this with options or more intelligent parsing&sniffing
  if (!address.city && address.state) {
    address.city = address.state;
    address.state = '';
  }
  if (!address.street) {
    address.street = address.city;
    address.city = '';
  }

  return address;
}

// get list of objects with discrete address properties
var addresses = rawlist
  .filter(function(o) {
    return o.length > 0
  })
  .map(ParseAddressEsri);
$("#output").text(JSON.stringify(addresses));
console.log(addresses);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<textarea>
27488 Stanford Ave, Bowden, North Dakota
380 New York St, Redlands, CA 92373
13212 E SPRAGUE AVE, FAIR VALLEY, MD 99201
1005 N Gravenstein Highway, Sebastopol CA 95472
A. P. Croll &amp; Son 2299 Lewes-Georgetown Hwy, Georgetown, DE 19947
11522 Shawnee Road, Greenwood, DE 19950
144 Kings Highway, S.W. Dover, DE 19901
Intergrated Const. Services 2 Penns Way Suite 405, New Castle, DE 19720
Humes Realty 33 Bridle Ridge Court, Lewes, DE 19958
Nichols Excavation 2742 Pulaski Hwy, Newark, DE 19711
2284 Bryn Zion Road, Smyrna, DE 19904
VEI Dover Crossroads, LLC 1500 Serpentine Road, Suite 100 Baltimore MD 21
580 North Dupont Highway, Dover, DE 19901
P.O. Box 778, Dover, DE 19903
714 S OAK ST
714 S OAK ST, RUM TOWN, VA, 99201
3142 E SPRAGUE AVE, WHISKEY VALLEY, WA 99281
27488 Stanford Ave, Bowden, North Dakota
380 New York St, Redlands, CA 92373
</textarea>
<div id="output">
</div>
Pochard answered 15/3, 2018 at 18:59 Comment(2)
disclaimer: my clients own their address data and run their own Esri servers. If you grab data from google, OSM, ArcGisOnline, or wherever, make sure it is OK to store and use it (many services have restrictions on how you can store, and for how long)Pochard
The first answer above makes a compelling case that this problem is unsolvable with regexes if you're dealing with a global address list. 200 countries have too many exceptions. In my testing, you can determine the country from a string rather reliably, then look up a specifc regex for each country - which is probably how the better APIs work.Woollyheaded
F
2

For U.S. address parsing, I prefer using the usaddress package that is available in pip.

python3 -m pip install usaddress

Usage sample:

#!/usr/bin/env python3
# -*- coding: utf-8 -*-

# address_parser.py
import sys
from usaddress import tag
from json import dumps, loads

if __name__ == '__main__':
    tag_mapping = {
        'Recipient': 'recipient',
        'AddressNumber': 'addressStreet',
        'AddressNumberPrefix': 'addressStreet',
        'AddressNumberSuffix': 'addressStreet',
        'StreetName': 'addressStreet',
        'StreetNamePreDirectional': 'addressStreet',
        'StreetNamePreModifier': 'addressStreet',
        'StreetNamePreType': 'addressStreet',
        'StreetNamePostDirectional': 'addressStreet',
        'StreetNamePostModifier': 'addressStreet',
        'StreetNamePostType': 'addressStreet',
        'CornerOf': 'addressStreet',
        'IntersectionSeparator': 'addressStreet',
        'LandmarkName': 'addressStreet',
        'USPSBoxGroupID': 'addressStreet',
        'USPSBoxGroupType': 'addressStreet',
        'USPSBoxID': 'addressStreet',
        'USPSBoxType': 'addressStreet',
        'BuildingName': 'addressStreet',
        'OccupancyType': 'addressStreet',
        'OccupancyIdentifier': 'addressStreet',
        'SubaddressIdentifier': 'addressStreet',
        'SubaddressType': 'addressStreet',
        'PlaceName': 'addressCity',
        'StateName': 'addressState',
        'ZipCode': 'addressPostalCode',
    }
    try:
        address, _ = tag(' '.join(sys.argv[1:]), tag_mapping=tag_mapping)
    except:
        with open('failed_address.txt', 'a') as fp:
            fp.write(sys.argv[1] + '\n')
        print(dumps({}))
    else:
        print(dumps(dict(address)))

Running address_parser.py:

python3 address_parser.py 9757 East Arcadia Ave. Saugus MA 01906
{"addressStreet": "9757 East Arcadia Ave.", "addressCity": "Saugus", "addressState": "MA", "addressPostalCode": "01906"}
Failsafe answered 4/6, 2019 at 23:27 Comment(0)
R
1

I'm late to the party, but here is an Excel VBA script I wrote years ago for Australia. It can be easily modified to support other Countries. I've made a GitHub repository of the C# code here. I've hosted it on my site and you can download it here: http://jeremythompson.net/Rocks/ParseAddress.xlsm

Strategy

For any country with a PostCode that's numeric or can be matched with a RegEx my strategy works very well:

  1. First we detect the First and Surname which are assumed to be the top line. Its easy to skip the name and start with the address by unticking the checkbox (called 'Name is top row' as shown below).

  2. Next its safe to expect the Address consisting of the Street and Number come before the Suburb and the St, Pde, Ave, Av, Rd, Cres, loop, etc is a separator.

  3. Detecting the Suburb vs the State and even Country can trick the most sophisticated parsers as there can be conflicts. To overcome this I use a PostCode look up based on the fact that after stripping Street and Apartment/Unit numbers as well as the PoBox,Ph,Fax,Mobile etc, only the PostCode number will remain. This is easy to match with a regEx to then look up the suburb(s) and country.

    Your National Post Office Service will provide a list of post codes with Suburbs and States free of charge that you can store in an excel sheet, db table, text/json/xml file, etc.

  4. Finally, since some Post Codes have multiple Suburbs we check which suburb appears in the Address.


Example

Screenshot of Excel cells

VBA Code

DISCLAIMER, I know this code is not perfect, or even written well however its very easy to convert to any programming language and run in any type of application. The strategy is the answer depending on your country and rules, take this code as an example:

Option Explicit

Private Const TopRow As Integer = 0

Public Sub ParseAddress()
Dim strArr() As String
Dim sigRow() As String
Dim i As Integer
Dim j As Integer
Dim k As Integer
Dim Stat As String
Dim SpaceInName As Integer
Dim Temp As String
Dim PhExt As String

On Error Resume Next

Temp = ActiveSheet.Range("Address")

'Split info into array
strArr = Split(Temp, vbLf)

'Trim the array
For i = 0 To UBound(strArr)
strArr(i) = VBA.Trim(strArr(i))
Next i

'Remove empty items/rows    
ReDim sigRow(LBound(strArr) To UBound(strArr))
For i = LBound(strArr) To UBound(strArr)
    If Trim(strArr(i)) <> "" Then
        sigRow(j) = strArr(i)
        j = j + 1
    End If
Next i
ReDim Preserve sigRow(LBound(strArr) To j)

'Find the name (MUST BE ON THE FIRST ROW UNLESS CHECKBOX UNTICKED)
i = TopRow
If ActiveSheet.Shapes("chkFirst").ControlFormat.Value = 1 Then

SpaceInName = InStr(1, sigRow(i), " ", vbTextCompare) - 1

If ActiveSheet.Shapes("chkConfirm").ControlFormat.Value = 0 Then
ActiveSheet.Range("FirstName") = VBA.Left(sigRow(i), SpaceInName)
Else
 If MsgBox("First Name: " & VBA.Mid$(sigRow(i), 1, SpaceInName), vbQuestion + vbYesNo, "Confirm Details") = vbYes Then ActiveSheet.Range("FirstName") = VBA.Left(sigRow(i), SpaceInName)
End If

If ActiveSheet.Shapes("chkConfirm").ControlFormat.Value = 0 Then
ActiveSheet.Range("Surname") = VBA.Mid(sigRow(i), SpaceInName + 2)
Else
  If MsgBox("Surame: " & VBA.Mid(sigRow(i), SpaceInName + 2), vbQuestion + vbYesNo, "Confirm Details") = vbYes Then ActiveSheet.Range("Surname") = VBA.Mid(sigRow(i), SpaceInName + 2)
End If
sigRow(i) = ""
End If

'Find the Street by looking for a "St, Pde, Ave, Av, Rd, Cres, loop, etc"
For i = 1 To UBound(sigRow)
If Len(sigRow(i)) > 0 Then
    For j = 0 To 8
    If InStr(1, VBA.UCase(sigRow(i)), Street(j), vbTextCompare) > 0 Then
    
    'Find the position of the street in order to get the suburb
    SpaceInName = InStr(1, VBA.UCase(sigRow(i)), Street(j), vbTextCompare) + Len(Street(j)) - 1
    
    'If its a po box then add 5 chars
    If VBA.Right(Street(j), 3) = "BOX" Then SpaceInName = SpaceInName + 5
    
    If ActiveSheet.Shapes("chkConfirm").ControlFormat.Value = 0 Then
    ActiveSheet.Range("Street") = VBA.Mid(sigRow(i), 1, SpaceInName)
    Else
      If MsgBox("Street Address: " & VBA.Mid(sigRow(i), 1, SpaceInName), vbQuestion + vbYesNo, "Confirm Details") = vbYes Then ActiveSheet.Range("Street") = VBA.Mid(sigRow(i), 1, SpaceInName)
    End If
    'Trim the Street, Number leaving the Suburb if its exists on the same line
    sigRow(i) = VBA.Mid(sigRow(i), SpaceInName) + 2
    sigRow(i) = Replace(sigRow(i), VBA.Mid(sigRow(i), 1, SpaceInName), "")
    
    GoTo PastAddress:
    End If
    Next j
End If
Next i
PastAddress:

'Mobile
For i = 1 To UBound(sigRow)
If Len(sigRow(i)) > 0 Then
    For j = 0 To 3
    Temp = Mb(j)
        If VBA.Left(VBA.UCase(sigRow(i)), Len(Temp)) = Temp Then
        If ActiveSheet.Shapes("chkConfirm").ControlFormat.Value = 0 Then
        ActiveSheet.Range("Mobile") = VBA.Mid(sigRow(i), Len(Temp) + 2)
        Else
          If MsgBox("Mobile: " & VBA.Mid(sigRow(i), Len(Temp) + 2), vbQuestion + vbYesNo, "Confirm Details") = vbYes Then ActiveSheet.Range("Mobile") = VBA.Mid(sigRow(i), Len(Temp) + 2)
        End If
    sigRow(i) = ""
    GoTo PastMobile:
    End If
    Next j
End If
Next i
PastMobile:

'Phone
For i = 1 To UBound(sigRow)
If Len(sigRow(i)) > 0 Then
    For j = 0 To 1
    Temp = Ph(j)
        If VBA.Left(VBA.UCase(sigRow(i)), Len(Temp)) = Temp Then
            
            'TODO: Detect the intl or national extension here.. or if we can from the postcode.
            If ActiveSheet.Shapes("chkConfirm").ControlFormat.Value = 0 Then
            ActiveSheet.Range("Phone") = VBA.Mid(sigRow(i), Len(Temp) + 3)
            Else
              If MsgBox("Phone: " & VBA.Mid(sigRow(i), Len(Temp) + 3), vbQuestion + vbYesNo, "Confirm Details") = vbYes Then ActiveSheet.Range("Phone") = VBA.Mid(sigRow(i), Len(Temp) + 3)
            End If
        
        sigRow(i) = ""
        GoTo PastPhone:
        End If
    Next j
End If
Next i
PastPhone:


'Email
For i = 1 To UBound(sigRow)
    If Len(sigRow(i)) > 0 Then
        'replace with regEx search
        If InStr(1, sigRow(i), "@", vbTextCompare) And InStr(1, VBA.UCase(sigRow(i)), ".CO", vbTextCompare) Then
        Dim email As String
        email = sigRow(i)
        email = Replace(VBA.UCase(email), "EMAIL:", "")
        email = Replace(VBA.UCase(email), "E-MAIL:", "")
        email = Replace(VBA.UCase(email), "E:", "")
        email = Replace(VBA.UCase(Trim(email)), "E ", "")
        email = VBA.LCase(email)
        
            If ActiveSheet.Shapes("chkConfirm").ControlFormat.Value = 0 Then
            ActiveSheet.Range("Email") = email
            Else
              If MsgBox("Email: " & email, vbQuestion + vbYesNo, "Confirm Details") = vbYes Then ActiveSheet.Range("Email") = email
            End If
        sigRow(i) = ""
        Exit For
        End If
    End If
Next i

'Now the only remaining items will be the postcode, suburb, country
'there shouldn't be any numbers (eg. from PoBox,Ph,Fax,Mobile) except for the Post Code

'Join the string and filter out the Post Code
Temp = Join(sigRow, vbCrLf)
Temp = Trim(Temp)

For i = 1 To Len(Temp)

Dim postCode As String
postCode = VBA.Mid(Temp, i, 4)
    
'In Australia PostCodes are 4 digits
If VBA.Mid(Temp, i, 1) <> " " And IsNumeric(postCode) Then

    If ActiveSheet.Shapes("chkConfirm").ControlFormat.Value = 0 Then
    ActiveSheet.Range("PostCode") = postCode
    Else
      If MsgBox("Post Code: " & postCode, vbQuestion + vbYesNo, "Confirm Details") = vbYes Then ActiveSheet.Range("PostCode") = postCode
    End If

    'Lookup the Suburb and State based on the PostCode, the PostCode sheet has the lookup
    Dim mySuburbArray As Range
    Set mySuburbArray = Sheets("PostCodes").Range("A2:B16670")
    
    Dim suburbs As String
    For j = 1 To mySuburbArray.Columns(1).Cells.Count
    If mySuburbArray.Cells(j, 1) = postCode Then
        'Check if the suburb is listed in the address
        If InStr(1, UCase(Temp), mySuburbArray.Cells(j, 2), vbTextCompare) > 0 Then

        'Set the Suburb and State
        ActiveSheet.Range("Suburb") = mySuburbArray.Cells(j, 2)
        Stat = mySuburbArray.Cells(j, 3)
        ActiveSheet.Range("State") = Stat
                
        'Knowing the State - for Australia we can get the telephone Ext
        PhExt = PhExtension(VBA.UCase(Stat))
        ActiveSheet.Range("PhExt") = PhExt
        
        'remove the phone extension from the number
        Dim prePhone As String
        prePhone = ActiveSheet.Range("Phone")
        prePhone = Replace(prePhone, PhExt & " ", "")
        prePhone = Replace(prePhone, "(" & PhExt & ") ", "")
        prePhone = Replace(prePhone, "(" & PhExt & ")", "")
        ActiveSheet.Range("Phone") = prePhone
        Exit For
        End If
    End If
    Next j
Exit For
End If
Next i

End Sub

  
Private Function PhExtension(ByVal State As String) As String
Select Case State
Case Is = "NSW"
PhExtension = "02"
Case Is = "QLD"
PhExtension = "07"
Case Is = "VIC"
PhExtension = "03"
Case Is = "NT"
PhExtension = "04"
Case Is = "WA"
PhExtension = "05"
Case Is = "SA"
PhExtension = "07"
Case Is = "TAS"
PhExtension = "06"
End Select
End Function

Private Function Ph(ByVal Num As Integer) As String
Select Case Num
Case Is = 0
Ph = "PH"
Case Is = 1
Ph = "PHONE"
'Case Is = 2
'Ph = "P"
End Select
End Function

Private Function Mb(ByVal Num As Integer) As String
Select Case Num
Case Is = 0
Mb = "MB"
Case Is = 1
Mb = "MOB"
Case Is = 2
Mb = "CELL"
Case Is = 3
Mb = "MOBILE"
'Case Is = 4
'Mb = "M"
End Select
End Function

Private Function Fax(ByVal Num As Integer) As String
Select Case Num
Case Is = 0
Fax = "FAX"
Case Is = 1
Fax = "FACSIMILE"
'Case Is = 2
'Fax = "F"
End Select
End Function

Private Function State(ByVal Num As Integer) As String
Select Case Num
Case Is = 0
State = "NSW"
Case Is = 1
State = "QLD"
Case Is = 2
State = "VIC"
Case Is = 3
State = "NT"
Case Is = 4
State = "WA"
Case Is = 5
State = "SA"
Case Is = 6
State = "TAS"
End Select
End Function

Private Function Street(ByVal Num As Integer) As String
Select Case Num
Case Is = 0
Street = " ST"
Case Is = 1
Street = " RD"
Case Is = 2
Street = " AVE"
Case Is = 3
Street = " AV"
Case Is = 4
Street = " CRES"
Case Is = 5
Street = " LOOP"
Case Is = 6
Street = "PO BOX"
Case Is = 7
Street = " STREET"
Case Is = 8
Street = " ROAD"
Case Is = 9
Street = " AVENUE"
Case Is = 10
Street = " CRESENT"
Case Is = 11
Street = " PARADE"
Case Is = 12
Street = " PDE"
Case Is = 13
Street = " LANE"
Case Is = 14
Street = " COURT"
Case Is = 15
Street = " BLVD"
Case Is = 16
Street = "P.O. BOX"
Case Is = 17
Street = "P.O BOX"
Case Is = 18
Street = "PO BOX"
Case Is = 19
Street = "POBOX"
End Select
End Function
Rael answered 25/8, 2019 at 11:40 Comment(0)

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