In my windows-only program, I use a third-party library, which returns a HBITMAP
.
Is there a way to initialize a QImage
from its contents, i.e. to convert it to a QImage
?
In my windows-only program, I use a third-party library, which returns a HBITMAP
.
Is there a way to initialize a QImage
from its contents, i.e. to convert it to a QImage
?
This is the way to do it for Qt 4 (QtGui):
QImage image(QPixmap::fromWinHBITMAP(hBitmap).toImage());
This is the way to do it for Qt 5 (QtWinExtras):
QPixmap pixmap = QtWin::fromHBITMAP(hBitmap);
QImage image = pixmap.toImage();
// or
QtWin::imageFromHBITMAP(hdc, hBitmap, width, height)
OK, this seems to work for me:
QImage image(QPixmap::fromWinHBITMAP(hBitmap).toImage());
Qt5 without Extras: Put before your code
#include <QPixmap>
Q_GUI_EXPORT QPixmap qt_pixmapFromWinHBITMAP(HBITMAP bitmap, int hbitmapFormat=0);
and in your function, for example
QPixmap pixmap = qt_pixmapFromWinHBITMAP(LoadBitmap(uiID));
Cheers
As of Qt 6.0, you could use the static QImage::fromHBITMAP(HBITMAP hbitmap):
Returns a QImage that is equivalent to the given hbitmap.
HBITMAP does not store information about the alpha channel.
In the standard case, the alpha channel is ignored and a fully opaque image is created (typically of >format QImage::Format_RGB32).
There are cases where the alpha channel is used, though, for example for application icon or systray icons. In that case, reinterpretAsFormat(QImage::Format_ARGB32) should be called on the returned image to ensure the format is correct.
This function was introduced in Qt 6.0.
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fromWinHBITMAP
is now part ofQImage
natively, so you can just callQImage.fromHBITMAP
. – Bataan