How to create an object for a Django model with a many to many field?
Asked Answered
D

6

176

My model:

class Sample(models.Model):
    users = models.ManyToManyField(User)

I want to save both user1 and user2 in that model:

user1 = User.objects.get(pk=1)
user2 = User.objects.get(pk=2)
sample_object = Sample(users=user1, users=user2)
sample_object.save()

I know that's wrong, but I'm sure you get what I want to do. How would you do it ?

Duggins answered 9/8, 2011 at 12:26 Comment(0)
A
288

You cannot create m2m relations from unsaved objects. If you have the pks, try this:

sample_object = Sample()
sample_object.save()
sample_object.users.add(1,2)

Update: After reading the saverio's answer, I decided to investigate the issue a bit more in depth. Here are my findings.

This was my original suggestion. It works, but isn't optimal. (Note: I'm using Bars and a Foo instead of Users and a Sample, but you get the idea).

bar1 = Bar.objects.get(pk=1)
bar2 = Bar.objects.get(pk=2)
foo = Foo()
foo.save()
foo.bars.add(bar1)
foo.bars.add(bar2)

It generates a whopping total of 7 queries:

SELECT "app_bar"."id", "app_bar"."name" FROM "app_bar" WHERE "app_bar"."id" = 1
SELECT "app_bar"."id", "app_bar"."name" FROM "app_bar" WHERE "app_bar"."id" = 2
INSERT INTO "app_foo" ("name") VALUES ()
SELECT "app_foo_bars"."bar_id" FROM "app_foo_bars" WHERE ("app_foo_bars"."foo_id" = 1  AND "app_foo_bars"."bar_id" IN (1))
INSERT INTO "app_foo_bars" ("foo_id", "bar_id") VALUES (1, 1)
SELECT "app_foo_bars"."bar_id" FROM "app_foo_bars" WHERE ("app_foo_bars"."foo_id" = 1  AND "app_foo_bars"."bar_id" IN (2))
INSERT INTO "app_foo_bars" ("foo_id", "bar_id") VALUES (1, 2)

I'm sure we can do better. You can pass multiple objects to the add() method:

bar1 = Bar.objects.get(pk=1)
bar2 = Bar.objects.get(pk=2)
foo = Foo()
foo.save()
foo.bars.add(bar1, bar2)

As we can see, passing multiple objects saves one SELECT:

SELECT "app_bar"."id", "app_bar"."name" FROM "app_bar" WHERE "app_bar"."id" = 1
SELECT "app_bar"."id", "app_bar"."name" FROM "app_bar" WHERE "app_bar"."id" = 2
INSERT INTO "app_foo" ("name") VALUES ()
SELECT "app_foo_bars"."bar_id" FROM "app_foo_bars" WHERE ("app_foo_bars"."foo_id" = 1  AND "app_foo_bars"."bar_id" IN (1, 2))
INSERT INTO "app_foo_bars" ("foo_id", "bar_id") VALUES (1, 1)
INSERT INTO "app_foo_bars" ("foo_id", "bar_id") VALUES (1, 2)

I wasn't aware that you can also assign a list of objects:

bar1 = Bar.objects.get(pk=1)
bar2 = Bar.objects.get(pk=2)
foo = Foo()
foo.save()
foo.bars = [bar1, bar2]

Unfortunately, that creates one additional SELECT:

SELECT "app_bar"."id", "app_bar"."name" FROM "app_bar" WHERE "app_bar"."id" = 1
SELECT "app_bar"."id", "app_bar"."name" FROM "app_bar" WHERE "app_bar"."id" = 2
INSERT INTO "app_foo" ("name") VALUES ()
SELECT "app_foo_bars"."id", "app_foo_bars"."foo_id", "app_foo_bars"."bar_id" FROM "app_foo_bars" WHERE "app_foo_bars"."foo_id" = 1
SELECT "app_foo_bars"."bar_id" FROM "app_foo_bars" WHERE ("app_foo_bars"."foo_id" = 1  AND "app_foo_bars"."bar_id" IN (1, 2))
INSERT INTO "app_foo_bars" ("foo_id", "bar_id") VALUES (1, 1)
INSERT INTO "app_foo_bars" ("foo_id", "bar_id") VALUES (1, 2)

Let's try to assign a list of pks, as saverio suggested:

foo = Foo()
foo.save()
foo.bars = [1,2]

As we don't fetch the two Bars, we save two SELECT statements, resulting in a total of 5:

INSERT INTO "app_foo" ("name") VALUES ()
SELECT "app_foo_bars"."id", "app_foo_bars"."foo_id", "app_foo_bars"."bar_id" FROM "app_foo_bars" WHERE "app_foo_bars"."foo_id" = 1
SELECT "app_foo_bars"."bar_id" FROM "app_foo_bars" WHERE ("app_foo_bars"."foo_id" = 1  AND "app_foo_bars"."bar_id" IN (1, 2))
INSERT INTO "app_foo_bars" ("foo_id", "bar_id") VALUES (1, 1)
INSERT INTO "app_foo_bars" ("foo_id", "bar_id") VALUES (1, 2)

And the winner is:

foo = Foo()
foo.save()
foo.bars.add(1,2)

Passing pks to add() gives us a total of 4 queries:

INSERT INTO "app_foo" ("name") VALUES ()
SELECT "app_foo_bars"."bar_id" FROM "app_foo_bars" WHERE ("app_foo_bars"."foo_id" = 1  AND "app_foo_bars"."bar_id" IN (1, 2))
INSERT INTO "app_foo_bars" ("foo_id", "bar_id") VALUES (1, 1)
INSERT INTO "app_foo_bars" ("foo_id", "bar_id") VALUES (1, 2)
Azikiwe answered 9/8, 2011 at 12:43 Comment(4)
I'd like to add, you can pass a list with * like so: foo.bars.add(*list) and it will explode the list into arguments :DYoung
This should be the Django Docs about ManyToMany! much clearer then docs.djangoproject.com/en/1.10/topics/db/examples/many_to_many or docs.djangoproject.com/en/1.10/ref/models/fields, and also with the performance penalties for the different method included. Maybe you can update it for Django 1.9? (the set method)Huxham
I want to save model with single id with more then one item and quantity. Will it be possible?? class Cart(models.Model): item = models.ForeignKey(Item, verbose_name="item") quantity = models.PositiveIntegerField(default=1)Cutlass
Wow. I'm amazed. :DAixlachapelle
C
134

For future visitors, you can create an object and all of its m2m objects in 2 queries using the new bulk_create in django 1.4. Note that this is only usable if you don't require any pre or post-processing on the data with save() methods or signals. What you insert is exactly what will be in the DB

You can do this without specifying a "through" model on the field. For completeness, the example below creates a blank Users model to mimic what the original poster was asking.

from django.db import models

class Users(models.Model):
    pass

class Sample(models.Model):
    users = models.ManyToManyField(Users)

Now, in a shell or other code, create 2 users, create a sample object, and bulk add the users to that sample object.

for _ in range(2):  # Create some Users
    Users().save()

users = Users.objects.filter(pk__in=[1,2])

sample_object = Sample()
sample_object.save()

# Access the through model directly
ThroughModel = Sample.users.through
ThroughModel.objects.bulk_create([
    ThroughModel(users_id=users[0].pk, sample_id=sample_object.pk),
    ThroughModel(users_id=users[1].pk, sample_id=sample_object.pk)
])
Castra answered 12/4, 2012 at 2:2 Comment(2)
I'm trying to use your answer here but I'm getting stuck. Thoughts?Hyperkinesia
Hmm, this worked for me, but I had to set the attributes in bulk_create to the model instances, not the IDs.Davidson
C
20

Django 1.9
A quick example:

sample_object = Sample()
sample_object.save()

list_of_users = DestinationRate.objects.all()
sample_object.users.set(list_of_users)
Cinnamon answered 22/6, 2016 at 15:59 Comment(0)
R
9

RelatedObjectManagers are different "attributes" than fields in a Model. The simplest way to achieve what you are looking for is

sample_object = Sample.objects.create()
sample_object.users = [1, 2]

That's the same as assigning a User list, without the additional queries and the model building.

If the number of queries is what bothers you (instead of simplicity), then the optimal solution requires three queries:

sample_object = Sample.objects.create()
sample_id = sample_object.id
sample_object.users.through.objects.create(user_id=1, sample_id=sample_id)
sample_object.users.through.objects.create(user_id=2, sample_id=sample_id)

This will work because we already know that the 'users' list is empty, so we can create mindlessly.

Remediable answered 9/8, 2011 at 15:48 Comment(0)
N
3

You could replace the set of related objects in this way (new in Django 1.9):

new_list = [user1, user2, user3]
sample_object.related_set.set(new_list)
Nipple answered 28/2, 2016 at 14:36 Comment(0)
D
-1

If someone is looking to do David Marbles answer on a self referring ManyToMany field. The ids of the through model are called: "to_'model_name_id" and "from_'model_name'_id".

If that doesn't work you can check the django connection.

Deciduous answered 20/6, 2020 at 12:33 Comment(0)

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