Is C++ function call an expression?

Question

A function produces a result, can be used as argument of another function parameter. So, is a function call like:

f(1,2,3)

be considered as an "expression"? Thanks.

Manipulate

Yes, its a postfix-expression (function name) with a expression-list (arguments). See : msdn.microsoft.com/en-us/library/2az68d4d.aspx – Yare

@molbdnilo: I'm sure comments can be very short, e.g., just two characters. Here is an example: // ;-) – Lemley

Of course real programming languages can do it with only one character # (yes, I'm trolling too). – Immiscible

@DietmarKühl It's Stack Exchange comments that can't be short. – Viperish

@juanchopanza OK, it's gone. – Galliett

@PaulStelian That was the joke. – Galliett

What made you think there could possibly be some other option? – Bombe

Answer 1

The C++ standard (N3376, §5.1) specifies an expression as:

An expression is a sequence of operators and operands that specifies a computation. An expression can result in a value and can cause side effects.

Further in the same section (§5.2.2):

A function call is a postfix expression followed by parentheses containing a possibly empty, comma-separated list of expressions which constitute the arguments to the function.

In short, yes.

Som

I suppose the same can be said about JavaScript? – Gamesome

Answer 2

According to 5.2.2 [expr.call] paragraph 1 of ISO/IEC 14882:2014, a function call is a [postfix] expression:

A function call is a postfix expression followed by parentheses containing a possibly empty, comma-separated list of initializer-clauses which constitute the arguments to the function. ...

Digiovanni