tapply() function dependent on multiple columns in R
Asked Answered
L

3

7

In R, I have a table with Location, sample_year and count. So,

Location sample_year count  
A        1995        1
A        1995        1  
A        2000        3  
B        2000        1  
B        2000        1  
B        2000        5

I want a summary table that examines both the 'Location' and 'sample_year' columns and sums 'count' dependent on this unique combination instead of just a single column. So, end result should be:

Location sample_year sum_count
A        1995        2
A        2000        3
B        2000        7

I could merge columns and data into a new column to create unique a Location-sample_year but this is not a clean solution, esp if I need to scale it up to three columns at some point. There must be a better approach.

Lactescent answered 7/3, 2011 at 5:3 Comment(1)
This is not really a tapply() question, perhaps edit the title to be more general? You can get the sum with tapply, but still need to clean up the aggregated columns: tapply(x$count, paste(x$Location, x$sample_year), sum)Hypoploid
H
11

You can use aggregate with a formula.

First the data:

x <- read.table(textConnection("Location sample_year count  
A        1995        1
A        1995        1  
A        2000        3  
B        2000        1  
B        2000        1  
B        2000        5"), header = TRUE)

Aggregate using sum with a formula specifying the grouping:

aggregate(count ~ Location+sample_year, data = x, sum)
    Location sample_year count
1        A        1995     2
2        A        2000     3
3        B        2000     7
Hypoploid answered 7/3, 2011 at 5:24 Comment(3)
+1 Neat one-liner... It's always better to use functions available in base R distribution.Silberman
I would not say "always", there are easier to use tools like reshape (and plyr, and stringr, raster, ...) that can allow you to do more in smarter ways, I just haven't made the effort to learn and I get by with the older stuff because I just learnt that way. If I knew the new stuff I would suggest it as well, I voted on your answer!Hypoploid
IMHO, reshape pays off only in case of complex aggregation. plyr is another cool package that's really worth learning.Silberman
S
4

Or with reshape package:

library(reshape)
md <- melt(x, measure.vars = "count")
cast(md, Location + sample_year ~ variable, sum)
  Location sample_year count
1        A        1995     2
2        A        2000     3
3        B        2000     7

EDIT:

I used object x from @mdsumner's answer. Anyway... I recommend you to stick with his answer, since it doesn't depend on external packages (aggregate function comes bundled with R, unless you detach stats package...). And, BTW, it's faster than reshape solution.

Silberman answered 7/3, 2011 at 5:36 Comment(0)
D
2

Or with plyr (using x from @mdsummer)

library(plyr)
ddply(x, .(Location,sample_year), summarise, count = sum(count))
Dikmen answered 7/3, 2011 at 14:31 Comment(0)

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