How do you limit UILabel characters in swift?

Question

I'm trying to set a limit in my label to 10 characters, I'm a complete newbie to programming in general so its my 3rd month so far... anyway thanks in advance :-)

Vlada

Not even close to enough information and no code. – Takamatsu

Since you've already set a limit on yourself how can you expect to set one on a UILabel? – Jap

I think the question is pretty clear and don't need code just to limit characters on one label... It's not like I'm asking how to write a complicated function and then the code be necessary – Vlada

Answer 1

If you want to limit the UILabel to just 10 characters then you just have to assign it with a text with length of 10. You can use NSString and NSRange to extract the text you need.

let str = "This is a Very Long Label"
let nsString = str as NSString
if nsString.length >= 10
{
  label.text = nsString.substringWithRange(NSRange(location: 0, length: nsString.length > 10 ? 10 : nsString.length))
}

Saveall

Of course this code will crash if str has less than 10 characters in it to start with. – Ill

Answer 2

You can also create a String extension and reuse it with any text string.. You can do it in the following way:

create the extension:

extension String {
   func maxLength(length: Int) -> String {
       var str = self
       let nsString = str as NSString
       if nsString.length >= length {
           str = nsString.substring(with:
               NSRange(
                location: 0,
                length: nsString.length > length ? length : nsString.length)
           )
       }
       return  str
   }
}

you can use the extension in the following way:

label.text = "This is a Very Long Label".maxLength(length: 10)

the previous code was tested in Swift 5.0

Hackman

Answer 3

Check out this answer: https://mcmap.net/q/23464/-how-does-string-substring-work-in-swift

My version is (Swift 5+):

extension String {
    func shorted(to symbols: Int) -> String {
        guard self.count > symbols else {
            return self
        }
        return self.prefix(symbols) + " ..."
    }
}

Pawnbroker

Answer 4

SWIFT 3

        let str = GL_GetNews[indexPath.row]["n_body"].stringValue
        let nsString = str as NSString
        if nsString.length > 0
        {
             cell.newsDescription.text = nsString.substring(with: NSRange(location: 0, length: nsString.length > 200 ? 200 : nsString.length))
        }

Ricercare