Powershell loop with numbers to alphabet

Question

I need help with the following: Create a for loop based on the conditions that the index is initialized to 0, $test is less than 26, and the index is incremented by 1 For each iteration, print the current letter of the alphabet. Start at the letter A. Thus, for each iteration, a single letter is printed on a separate line. I am not able to increment the char each time the loop runs

for ($test = 0; $test -lt 26; $test++)
{
[char]65
}

I have tried multiple attempts with trying to increment the char 65 through 90 with no success. Is there an easier way to increment the alphabet to show a letter for each loop that is ran?

Mai

0=A 1=B 2=C 3=D ....25=Z – Mai

0..25 | %{ [char] ($_ + [byte][char] 'A') } – Comedic

if all you want it the range of uppercase letters, this will do it ... [char[]]('A'[0]..'Z'[0]). [grin] – Bolin

Answer 1

You can sum your loop index with 65. So, it'll be: 0 + 65 = A, 1 + 65 = B ...

for ($test = 0; $test -lt 26; $test++)
{
    [char](65 + $test)
}

Subclass

for ($test = 0; $test -lt 26; $test++) { $char = [char](65 +$test) Write-Host $char } Your suggestion worked out great. Thank you – Mai

Answer 2

PS2 to PS5:

97..(97+25) | % { [char]$_ }

Faster:

(97..(97+25)).ForEach({ [char]$_ })

PS6+:

'a'..'z' | % { $_ }

Faster:

('a'..'z').ForEach({ $_ })

Avenue

Answer 3

Here's a way to find the first available drive. It checks drives E to Z, and stops on the first available one:

101..(97+25) | % { if(!( get-psdrive ([char]$_ ) -ea 0 ) ) {$freedrive = ([char]$_ ); break} }
$freedrive

Gabrielgabriela

Answer 4

The following example does not assume 'A' is 65 and also allows you to change it to whatever starting drive you desire. For example, to start with 'C' and go to 'Z':

$start = 'C'
for ($next = 0; $next -lt (26 + [byte][char]'A' - [byte][char]$start); $next++) {
    [char]([byte][char]$start + $next)
}

Softball