Get file version in PowerShell
Asked Answered
C

11

187

How can you get the version information from a .dll or .exe file in PowerShell?

I am specifically interested in File Version, though other version information (that is, Company, Language, Product Name, etc.) would be helpful as well.

Cletis answered 27/8, 2008 at 17:28 Comment(0)
S
177

Since PowerShell can call .NET classes, you could do the following:

[System.Diagnostics.FileVersionInfo]::GetVersionInfo("somefilepath").FileVersion

Or as noted here on a list of files:

get-childitem * -include *.dll,*.exe | foreach-object { "{0}`t{1}" -f $_.Name, [System.Diagnostics.FileVersionInfo]::GetVersionInfo($_).FileVersion }

Or even nicer as a script: https://jtruher3.wordpress.com/2006/05/14/powershell-and-file-version-information/

Spiracle answered 27/8, 2008 at 17:45 Comment(6)
See @Mare for a solution that does not require a .NET object. IMHO Jaykul's response should have been selected as the answer :)Steatopygia
Although the other answers give shorter commands, all of the ones I tried print out too much info and truncate the file path to "...". The 2nd command in this answer gives just what you need, works for a directory of files, and is formatting in a way that it's easy to see how to modify it to return other info. Just change the .LegalCopyright in the command to .FileVersion.Licha
This is the correct version for .NET EXEs. Jaykul's answer doesn't get the same version.Afra
That's actually not right. Look at get-item C:\Windows\System32\ubpm.dll | % VersionInfo | fl * -force and compare the FilePrivatePart to the last part of the FileVersion. The FileVersion shows what originally shipped, and not the patched version. This command, on the other hand, shows the patched version number: (get-command C:\Windows\System32\ubpm.dll).VersionMare
A better example would be the recently patched C:\Windows\System32\Lsasrv.dll ... but the truth is that (Get-Command ... ).Version returns the ProductVersion not the FileVersion, and sometimes that matters. So for a full solution that actually returns the updated FileVersion, check out the Update-TypeData example in my answer below.Mare
log MethodInvocationException: Exception calling "GetVersionInfo" with "1" argument(s): "/home/rokejulianlockhart/PolicyPlus.exe" Callas
M
233

Since PowerShell 5 in Windows 10, you can look at FileVersionRaw (or ProductVersionRaw) on the output of Get-Item or Get-ChildItem, like this:

(Get-Item C:\Windows\System32\Lsasrv.dll).VersionInfo.FileVersionRaw

It's actually the same ScriptProperty from my Update-TypeData in the original answer below, but built-in now.

In PowerShell 4, you could get the FileVersionInfo from Get-Item or Get-ChildItem, but it would show the original FileVersion from the shipped product, and not the updated version. For instance:

(Get-Item C:\Windows\System32\Lsasrv.dll).VersionInfo.FileVersion

Interestingly, you could get the updated (patched) ProductVersion by using this:

(Get-Command C:\Windows\System32\Lsasrv.dll).Version

The distinction I'm making between "original" and "patched" is basically due to the way the FileVersion is calculated (see the docs here). Basically ever since Vista, the Windows API GetFileVersionInfo is querying part of the version information from the language neutral file (exe/dll) and the non-fixed part from a language-specific mui file (which isn't updated every time the files change).

So with a file like lsasrv (which got replaced due to security problems in SSL/TLS/RDS in November 2014) the versions reported by these two commands (at least for a while after that date) were different, and the second one is the more "correct" version.

However, although it's correct in LSASrv, it's possible for the ProductVersion and FileVersion to be different (it's common, in fact). So the only way to get the updated Fileversion straight from the assembly file is to build it up yourself from the parts, something like this:

Get-Item C:\Windows\System32\Lsasrv.dll | ft FileName, File*Part

Or by pulling the data from this:

[System.Diagnostics.FileVersionInfo]::GetVersionInfo($this.FullName)

You can easily add this to all FileInfo objects by updating the TypeData in PowerShell:

Update-TypeData -TypeName System.IO.FileInfo -MemberName FileVersionRaw -MemberType ScriptProperty -Value {
   [System.Diagnostics.FileVersionInfo]::GetVersionInfo($this.FullName) | % {
      [Version](($_.FileMajorPart, $_.FileMinorPart, $_.FileBuildPart, $_.FilePrivatePart)-join".") 
   }
}

Now every time you do Get-ChildItem or Get-Item you'll have a FileVersionRaw property that shows the updated File Version ...

Mare answered 15/9, 2008 at 19:33 Comment(14)
And to make this the equivalent of Lars' accepted answer, just use (Get-Command C:\Path\YourFile.Dll).FileVersionInfo.FileVersionJuttajutty
I am intrigued about the Get-Command applied to a dll file. Could you elaborate about its effect ?Thetes
Well, in the old days the FileInfo didn't have a "VersionInfo" ScriptProperty like it does now, but the ApplicationInfo object returned by Get-Command included a "FileVersionInfo" ScriptProperty (which is the same as the VersionInfo that's on the FileInfo objects in the newer versions of PowerShell).Mare
Warning The FileVersionInfo.FileVersion is a string representation that may not be up to date. You should look at FileVersionInfo.FileMajorPart, FileMinorPart, FileBuildPart, FilePrivatePart. See GetFileVersionInfo() returns wrong file's version informationAntalya
good blog post to support @bdeem's point: rohnspowershellblog.wordpress.com/2013/12/16/…Humic
This doesn't work when the path contains parenthesis, is e.g. c:\program files (x86)\myfile.dll. The error message is: The term 'x86' is not recognized as the name of a cmdlet, function, script file, or operable program How can be "escaped" the parenthesis characters from bad parsing?Duprey
I'm curious how the (presumably more recent) VersionInfo.ProductVersion property factors into this - does it handle this kind of edge case correctly?Exorbitance
@Duprey I would think you're talking about the (Get-Command ...).Version stuff? You just need to put quotes around your file path to avoid the parenthesis being interpreted as a sub-expression (and thus, as a command).Mare
@Exorbitance the ProductVersion and FileVersion need not be related at all. A file version is the version of the file, while the ProductVersion is the version of the product that the file is distributed with. Usually they're the same, but they can be completely different, depending on the source of the files. At work our files are versioned according to semver, but the product is versioned by the DATE, for marketing reasons ;-) See also learn.microsoft.com/en-us/windows/win32/menurc/…Mare
@Mare To clarify my earlier comment/question: the original answer demonstrates how to get the ProductVersion in PowerShell through some interesting convolutions, because ProductVersion may be more indicative than FileVersion. The original answer makes no mention of the VersionInfo.ProductVersion property, possibly because the answer pre-dates it. Is (Get-Item C:\Windows\System32\Lsasrv.dll).VersionInfo.ProductVersion a newer simpler way to get the same ProductVersion information as documented in the answer? I don't really trust Microsoft to use the term ProductVersion consistently.Exorbitance
@Exorbitance It's not new. You can look it up on docs and see how far back it goes (.NET 1.1) 😏. My answer mentions ProductVersion, but the version we're calculating with all that ScriptProperty code is the real FILE Version, not the ProductVersion. They are sometimes the same, but not always. 😔 And unfortunately, every real-world example I come up with changes in the next service release of Windows 😉 learn.microsoft.com/en-us/dotnet/api/…Mare
I originally mentioned it because at the time, the assembly in question had a DIFFERENT FileVersion and ProductVersion, but the calculated file version happened to match the ProductVersion.Mare
As of PS 5.1 (possibly earlier, I didn't check), there are new VersionInfo properties FileVersionRaw and ProductVersionRaw, which work like the ScriptProperty in this answer, so you can just write (Get-Item SomeFile).VersionInfo.FileVersionRaw.Trevortrevorr
Yeah, @Trevortrevorr is right, those were added in PowerShell 5! devblogs.microsoft.com/scripting/…Mare
S
177

Since PowerShell can call .NET classes, you could do the following:

[System.Diagnostics.FileVersionInfo]::GetVersionInfo("somefilepath").FileVersion

Or as noted here on a list of files:

get-childitem * -include *.dll,*.exe | foreach-object { "{0}`t{1}" -f $_.Name, [System.Diagnostics.FileVersionInfo]::GetVersionInfo($_).FileVersion }

Or even nicer as a script: https://jtruher3.wordpress.com/2006/05/14/powershell-and-file-version-information/

Spiracle answered 27/8, 2008 at 17:45 Comment(6)
See @Mare for a solution that does not require a .NET object. IMHO Jaykul's response should have been selected as the answer :)Steatopygia
Although the other answers give shorter commands, all of the ones I tried print out too much info and truncate the file path to "...". The 2nd command in this answer gives just what you need, works for a directory of files, and is formatting in a way that it's easy to see how to modify it to return other info. Just change the .LegalCopyright in the command to .FileVersion.Licha
This is the correct version for .NET EXEs. Jaykul's answer doesn't get the same version.Afra
That's actually not right. Look at get-item C:\Windows\System32\ubpm.dll | % VersionInfo | fl * -force and compare the FilePrivatePart to the last part of the FileVersion. The FileVersion shows what originally shipped, and not the patched version. This command, on the other hand, shows the patched version number: (get-command C:\Windows\System32\ubpm.dll).VersionMare
A better example would be the recently patched C:\Windows\System32\Lsasrv.dll ... but the truth is that (Get-Command ... ).Version returns the ProductVersion not the FileVersion, and sometimes that matters. So for a full solution that actually returns the updated FileVersion, check out the Update-TypeData example in my answer below.Mare
log MethodInvocationException: Exception calling "GetVersionInfo" with "1" argument(s): "/home/rokejulianlockhart/PolicyPlus.exe" Callas
C
62

'dir' is an alias for Get-ChildItem which will return back a System.IO.FileInfo class when you're calling it from the filesystem which has VersionInfo as a property. So ...

To get the version info of a single file do this:

PS C:\Windows> (dir .\write.exe).VersionInfo | fl


OriginalFilename : write
FileDescription  : Windows Write
ProductName      : Microsoft® Windows® Operating System
Comments         :
CompanyName      : Microsoft Corporation
FileName         : C:\Windows\write.exe
FileVersion      : 6.1.7600.16385 (win7_rtm.090713-1255)
ProductVersion   : 6.1.7600.16385
IsDebug          : False
IsPatched        : False
IsPreRelease     : False
IsPrivateBuild   : False
IsSpecialBuild   : False
Language         : English (United States)
LegalCopyright   : © Microsoft Corporation. All rights reserved.
LegalTrademarks  :
PrivateBuild     :
SpecialBuild     :

For multiple files this:

PS C:\Windows> dir *.exe | %{ $_.VersionInfo }

ProductVersion   FileVersion      FileName
--------------   -----------      --------
6.1.7600.16385   6.1.7600.1638... C:\Windows\bfsvc.exe
6.1.7600.16385   6.1.7600.1638... C:\Windows\explorer.exe
6.1.7600.16385   6.1.7600.1638... C:\Windows\fveupdate.exe
6.1.7600.16385   6.1.7600.1638... C:\Windows\HelpPane.exe
6.1.7600.16385   6.1.7600.1638... C:\Windows\hh.exe
6.1.7600.16385   6.1.7600.1638... C:\Windows\notepad.exe
6.1.7600.16385   6.1.7600.1638... C:\Windows\regedit.exe
6.1.7600.16385   6.1.7600.1638... C:\Windows\splwow64.exe
1,7,0,0          1,7,0,0          C:\Windows\twunk_16.exe
1,7,1,0          1,7,1,0          C:\Windows\twunk_32.exe
6.1.7600.16385   6.1.7600.1638... C:\Windows\winhlp32.exe
6.1.7600.16385   6.1.7600.1638... C:\Windows\write.exe
Chorion answered 29/1, 2010 at 4:0 Comment(0)
M
21

I realise this has already been answered, but if anyone's interested in typing fewer characters, I believe this is the shortest way of writing this in PS v3+:

ls application.exe | % versioninfo
  • ls is an alias for Get-ChildItem
  • % is an alias for ForEach-Object
  • versioninfo here is a shorthand way of writing {$_.VersionInfo}

The benefit of using ls in this way is that you can easily adapt it to look for a given file within subfolders. For example, the following command will return version info for all files called application.exe within subfolders:

ls application.exe -r | % versioninfo
  • -r is an alias for -Recurse

You can further refine this by adding -ea silentlycontinue to ignore things like permission errors in folders you can't search:

ls application.exe -r -ea silentlycontinue | % versioninfo
  • -ea is an alias for -ErrorAction

Finally, if you are getting ellipses (...) in your results, you can append | fl to return the information in a different format. This returns much more detail, although formatted in a list, rather that on one line per result:

ls application.exe -r -ea silentlycontinue | % versioninfo | fl
  • fl is an alias for Format-List

I realise this is very similar to xcud's reply in that ls and dir are both aliases for Get-ChildItem. But I'm hoping my "shortest" method will help someone.

The final example could be written in long-hand in the following way:

Get-ChildItem -Filter application.exe -Recurse -ErrorAction SilentlyContinue | ForEach-Object {$_.VersionInfo} | Format-List

... but I think my way is cooler and, for some, easier to remember. (But mostly cooler).

Mok answered 21/6, 2018 at 11:23 Comment(0)
V
17

I prefer to install the PowerShell Community Extensions and just use the Get-FileVersionInfo function that it provides.

Like so:

Get-FileVersionInfo MyAssembly.dll

with output like:

ProductVersion   FileVersion      FileName
--------------   -----------      --------
1.0.2907.18095   1.0.2907.18095   C:\Path\To\MyAssembly.dll

I've used it against an entire directory of assemblies with great success.

Vanzant answered 5/9, 2008 at 12:54 Comment(0)
P
11

Just another way to do it is to use the built-in file access technique:

(get-item .\filename.exe).VersionInfo | FL

You can also get any particular property off the VersionInfo, thus:

(get-item .\filename.exe).VersionInfo.FileVersion

This is quite close to the dir technique.

Pelmas answered 5/8, 2011 at 16:35 Comment(1)
(get-item \\"$computerName"\"C$\Program Files\Symantec AntiVirus\VPDN_LU.exe").VersionInfo.FileVersion worked for me. I needed to add a computer name from a loop.Forestry
W
9

This is based on the other answers, but is exactly what I was after:

(Get-Command C:\Path\YourFile.Dll).FileVersionInfo.FileVersion
World answered 28/11, 2013 at 11:31 Comment(2)
I am intrigued about the Get-Command applied to a dll file. Could you elaborate about its effect (before even calling for the property FileVersionInfo) ?Thetes
dll files contain FileVersionInfo just as exe files do. Applying this command to the path will get the file version info!World
A
5
[System.Diagnostics.FileVersionInfo]::GetVersionInfo("Path\To\File.dll")
Amoritta answered 27/8, 2008 at 17:41 Comment(0)
E
4

I find this useful:

function Get-Version($filePath)
{
   $name = @{Name="Name";Expression= {split-path -leaf $_.FileName}}
   $path = @{Name="Path";Expression= {split-path $_.FileName}}
   dir -recurse -path $filePath | % { if ($_.Name -match "(.*dll|.*exe)$") {$_.VersionInfo}} | select FileVersion, $name, $path
}
Ezekiel answered 31/7, 2012 at 12:28 Comment(0)
Y
2

As EBGreen said, [System.Diagnostics.FileVersionInfo]::GetVersionInfo(path) will work, but remember that you can also get all the members of FileVersionInfo, for example:

[System.Diagnostics.FileVersionInfo]::GetVersionInfo(path).CompanyName

You should be able to use every member of FileVersionInfo documented here, which will get you basically anything you could ever want about the file.

Yachting answered 27/8, 2008 at 17:46 Comment(0)
A
1

Here an alternative method. It uses Get-WmiObject CIM_DATAFILE to select the version.

(Get-WmiObject -Class CIM_DataFile -Filter "Name='C:\\Windows\\explorer.exe'" | Select-Object Version).Version
Admix answered 6/8, 2014 at 17:30 Comment(1)
using a share path with spaces in the name, I got "The property 'Version' cannot be found on this object. Verify that the property exists."Farias

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