Javascript oddness with array of objects and indexOf
Asked Answered
D

2

8

Not quite grasping what's going on here. Given the array (arr):

[
    {
        "first_name": "Dan",
        "last_name": "Woodson",
        "id": 1
    },
    {
        "first_name": "Jen",
        "last_name": "Woodson",
        "id": 2
    },
    {
        "first_name": "Yoshi",
        "last_name": "Woodson",
        "id": 3
    }
]

And the object (obj):

{
    "first_name": "Yoshi",
    "last_name": "Woodson",
    "id": 3
}

Why would arr.indexOf(obj) return -1 (especially since I retrieved the object from the array using it's 'id' parameter earlier in the function)?

Drais answered 23/12, 2011 at 16:13 Comment(3)
What do you mean "Earlier in the function" ? You need to show us the code that you wrote which fails, not just some JSON.Esse
Can you post the actual code you're using, and/or put it on a fsFiddle?Questionary
This is because ({a:12}) === ({a:12}) is false. Objects in JavaScript are equal if they are the same object (same reference), not just the same values.Hereditable
S
6

Array.indexOf() will only work on objects if the supplied object is exactly the same object you put in.

An exact copy is insufficient, it has to be the exact same object, i.e. there must be some object in the array such that:

arr[i] === obj

You need to show how you retrieved the object.

Sarita answered 23/12, 2011 at 16:18 Comment(0)
S
1

I would like to see the retrieve function, but most likely you are not using the same reference. Because the following is true:

var a = {id: 3};
var b = [a];
b.indexOf(a); // 0
a.id = "not three";
b.indexOf(a); // still 0

However, the following will break:

var a = {id: 3};
var b = [{id: 3}];
b.indexOf(a); // -1 not the same object
Suboxide answered 23/12, 2011 at 16:18 Comment(0)

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