Generate page numbers using javascript/jquery?

Question

How to generate page numbers like the below using javascript/jquery?

If the 5 th page is selected i have to show 3,4 and 6,7 and also 1,last page with prev,next... Any suggestion....

EDIT:

How to work with json data that use these pagination div? (ie) My json data contains 50 records I want to 10 in page 1 and so on... How to paginate json data with these numbers...

I want a jquery function to pass currentpageno,lastpagenumber and the function should generate me page numbers like the below for me

If it is the first page

If it is in the middle,

If it is the last page,

Second EDIT:

I have tried this function but doesn't seem to get the desired result

function generatePages(currentPage, LastPage) {
    if (LastPage <= 5) {
        var pages = '';
        for(var i=1;i<=5;i++)
        {
            pages += "<a class='page-numbers' href='#'>" + i + "</a>"
        }
        $("#PagerDiv").append(pages);
    }
    if (LastPage > 5) {
        var pages = '';
        for (var i = 1; i <= 5; i++) {
            pages += "<a class='page-numbers' href='#'>" + i + "</a>"
        }
        $("#PagerDiv").append(pages);
    }
}

I have the lastPage and currentPage values please help me out getting this...

Mikes

You need to writ some actual code, on your own, probably using a for loop. – Gavan

@SLaks: lol'd. But actually, that isn't true either :D – Cheyney

Answer 1

What you are looking for is called "pagination" and there's (as always) a jQuery plugin that does the job for you:

http://d-scribe.de/webtools/jquery-pagination/demo/demo_options.htm

(Download it here)

---

Edit: Since you don't seem to be able to get it working, here is one way (of several different) how you can use the plugin.

Step 1: Generate markup from your JSON-data like the following:

<div id="display">
    <!-- This is the div where the visible page will be displayed -->
</div>

<div id="hiddenData">
    <!-- This is the div where you output your records -->
    <div class="record">
        <!-- create one record-div for each record you have in your JSON data -->
    </div>
    <div class="record">
    </div>
</div>

The idea is to copy the respective record to the display div when clicking on a page-link. Therefore, the plugin offers a pageSelect-callback function. Step 2 is to implement this function, for instance:

function pageselectCallback(pageIndex, jq){
    // Clone the record that should be displayed
    var newContent = $('#hiddenData div.record:eq('+pageIndex+')').clone();
    // Update the display container
    $('#display').empty().append(newContent);
    return false;
}

This would mean that you have one page per record. If you want to display multiple records per page, you have to modify the above function accordingly.

The third and final step is to initialize the whole thing correctly.

function initPagination() {
    // Hide the records... they shouldn't be displayed
    $("#hiddenData").css("display", "none");
    // Get the number of records
    var numEntries = $('#hiddenData div.result').length;
    // Create pagination element
    $("#pagination").pagination(numEntries, {
        num_edge_entries: 2,
        num_display_entries: 8, // number of page links displayed 
        callback: pageselectCallback,
        items_per_page: 1  // Adjust this value if you change the callback!
    });
}

So, you just have to generate the HTML markup from your JSON data and call the init-function afterwards.

It's not that difficult, is it?

Cheyney

json doesn't make any difference, so yes, it will work. Have a look at the sources of the demo page (the members.js, specifically). It shows you how to load data on demand... – Cheyney

@Mef documentation would be useful? – Mikes

@Mef one more issue with pagination plugin... Please look at this #2551646 – Mikes

Answer 2

yeah @SLaks is right. nothing too crazy here. You will have 2 variables currentPageNumber and lastPageNumber.

$("div.paginator").append("<a...>prev</a>");
$("div.paginator").append("<a...>1</a>");

for (x = (currentPageNumber - 2; x <= (currentPageNumber + 2); x++) {
    $("div.paginator").append("<a...>"+ x +"</a>");
} 

$("div.paginator").append("<a...>"+ lastPageNumber +"</a>");
$("div.paginator").append("<a...>next</a>");

// you could apply styles to and a tag in the div.paginator
// you could apply a special class to the a tag that matches the currentPageNumber 
// you can also bind some click events to each a tag and use the $(this).text() to grab the number of the page to go to

Valerianaceous

Yeah, or you could just do what @Mef said. That is pretty dope. Welcome to the days of not having to write you own code. Community/Social Programming ROCKS! – Valerianaceous

However, the most essential part is missing here. Where do the page numbers come from? – Cheyney

@Mef i use asp.net and i move my values using a hiddenfield and fetch them in jquery... – Mikes

oh, I didn't mean you, actually I referred to the sample code which is of course right, but covers only a very small part of the problem – Cheyney

@Mef i tried your and got this...img709.imageshack.us/img709/9509/pager2.jpg – Mikes

Answer 3

Use THIS or THAT plugin. They're both easy html pagination plugins. Put everything in the html at once and paginate with one of those.

Nasty

Answer 4

Add two new hidden inputs

<input type='hidden' id='current_page' />  
<input type='hidden' id='show_per_page' /> 

Next add an empty div to create pagination controls

<!-- An empty div which will be populated using jQuery -->  
<div id='page_navigation'></div>

$(document).ready(function(){

    //how much items per page to show
    var show_per_page = 5;
    //getting the amount of elements inside content div
    var number_of_items = $('#content').children().size();
    //calculate the number of pages we are going to have
    var number_of_pages = Math.ceil(number_of_items/show_per_page);

    //set the value of our hidden input fields
    $('#current_page').val(0);
    $('#show_per_page').val(show_per_page);

    //now when we got all we need for the navigation let's make it '

    /*
    what are we going to have in the navigation?
        - link to previous page
        - links to specific pages
        - link to next page
    */
    var navigation_html = '<a class="previous_link" href="javascript:previous();">Prev</a>';
    var current_link = 0;
    while(number_of_pages > current_link){
        navigation_html += '<a class="page_link" href="javascript:go_to_page(' + current_link +')" longdesc="' + current_link +'">'+ (current_link + 1) +'</a>';
        current_link++;
    }
    navigation_html += '<a class="next_link" href="javascript:next();">Next</a>';

    $('#page_navigation').html(navigation_html);

    //add active_page class to the first page link
    $('#page_navigation .page_link:first').addClass('active_page');

    //hide all the elements inside content div
    $('#content').children().css('display', 'none');

    //and show the first n (show_per_page) elements
    $('#content').children().slice(0, show_per_page).css('display', 'block');

});

function previous(){

    new_page = parseInt($('#current_page').val()) - 1;
    //if there is an item before the current active link run the function
    if($('.active_page').prev('.page_link').length==true){
        go_to_page(new_page);
    }

}

function next(){
    new_page = parseInt($('#current_page').val()) + 1;
    //if there is an item after the current active link run the function
    if($('.active_page').next('.page_link').length==true){
        go_to_page(new_page);
    }

}
function go_to_page(page_num){
    //get the number of items shown per page
    var show_per_page = parseInt($('#show_per_page').val());

    //get the element number where to start the slice from
    start_from = page_num * show_per_page;

    //get the element number where to end the slice
    end_on = start_from + show_per_page;

    //hide all children elements of content div, get specific items and show them
    $('#content').children().css('display', 'none').slice(start_from, end_on).css('display', 'block');

    /*get the page link that has longdesc attribute of the current page and add active_page class to it
    and remove that class from previously active page link*/
    $('.page_link[longdesc=' + page_num +']').addClass('active_page').siblings('.active_page').removeClass('active_page');

    //update the current page input field
    $('#current_page').val(page_num);
}

Sino