I'm using NetworkX 1.9.1.
I have a graph that I need to organize with positions and I then export to graphml format.
I've tried code in this question. It does not work, here is my example
import networkx as nx
import matplotlib.pyplot as plt
G = nx.read_graphml("colored.graphml")
pos=nx.spring_layout(G) # an example of quick positioning
nx.set_node_attributes(G, 'pos', pos)
nx.write_graphml(G, "g.graphml")
nx.draw_networkx(G, pos)
plt.savefig("g.pdf")
Here are the errors I get, the problem is how positions are saved (graphml does not accept arrays).
C:\Anaconda\python.exe C:/Users/sturaroa/Documents/PycharmProjects/node_labeling_test.py
Traceback (most recent call last):
File "C:/Users/sturaroa/Documents/PycharmProjects/node_labeling_test.py", line 11, in <module>
nx.write_graphml(G, "g.graphml")
File "<string>", line 2, in write_graphml
File "C:\Anaconda\lib\site-packages\networkx\utils\decorators.py", line 220, in _open_file
result = func(*new_args, **kwargs)
File "C:\Anaconda\lib\site-packages\networkx\readwrite\graphml.py", line 82, in write_graphml
writer.add_graph_element(G)
File "C:\Anaconda\lib\site-packages\networkx\readwrite\graphml.py", line 350, in add_graph_element
self.add_nodes(G,graph_element)
File "C:\Anaconda\lib\site-packages\networkx\readwrite\graphml.py", line 307, in add_nodes
self.add_attributes("node", node_element, data, default)
File "C:\Anaconda\lib\site-packages\networkx\readwrite\graphml.py", line 300, in add_attributes
scope=scope, default=default_value)
File "C:\Anaconda\lib\site-packages\networkx\readwrite\graphml.py", line 288, in add_data
'%s as data values.'%element_type)
networkx.exception.NetworkXError: GraphML writer does not support <type 'numpy.ndarray'> as data values.
I'm under the impression that I would be better off defining positions as 2 separate node attributes, x and y, and save them separately, defining a key for each of them in the graphml format, like this.
However, I'm not that familiar with Python, and would like your opinion before I make a mess iterating back and forth.
Thanks.