Use Reflection to call generic method on object instance with signature: SomeObject.SomeGenericInstanceMethod<T>(T argument)
Asked Answered
M

2

2

How do I call SomeObject.SomeGenericInstanceMethod<T>(T arg) ?

There are a few posts about calling generic methods, but not quite like this one. The problem is that the method argument parameter is constrained to the generic parameter.

I know that if the signature were instead

SomeObject.SomeGenericInstanceMethod<T>(string arg)

then I could get the MethodInfo with

typeof (SomeObject).GetMethod("SomeGenericInstanceMethod", new Type[]{typeof (string)}).MakeGenericMethod(typeof(GenericParameter))

So, How do I go about getting the MethodInfo when the regular arguments are of a generic type? Thanks!

Also, there may or may not be type constrains on the generic parameter.

Marsha answered 19/1, 2011 at 17:4 Comment(1)
possible duplicate of Select Right Generic Method with ReflectionTestate
T
11

You do it exactly the same way.

When you call MethodInfo.Invoke, you pass all the arguments in an object[] anyway, so it's not like you have to know the types at compile time.

Sample:

using System;
using System.Reflection;

class Test
{
    public static void Foo<T>(T item)
    {
        Console.WriteLine("{0}: {1}", typeof(T), item);
    }

    static void CallByReflection(string name, Type typeArg,
                                 object value)
    {
        // Just for simplicity, assume it's public etc
        MethodInfo method = typeof(Test).GetMethod(name);
        MethodInfo generic = method.MakeGenericMethod(typeArg);
        generic.Invoke(null, new object[] { value });
    }

    static void Main()
    {
        CallByReflection("Foo", typeof(object), "actually a string");
        CallByReflection("Foo", typeof(string), "still a string");
        // This would throw an exception
        // CallByReflection("Foo", typeof(int), "oops");
    }
}
Thelma answered 19/1, 2011 at 17:7 Comment(7)
Will this still work if there are multiple overloads for the method named "name"?Marsha
@smartcaveman: No, you'd need to work out which one to call. Calling GetMethod(string, Type[]) can get quite tricky when the parameter types are generic - I usually use GetMethods in conjunction with a LINQ query to find the right method.Thelma
Something like: typeof(Test).GetMethods(BindingFlags.Instance).Where(x=>x.IsGenericMethodDefinition & x.Name==name) ?Marsha
@smartcaveman: Well that wouldn't help if there were two generic methods with the same name. Basically I can't help you much here, because I don't know how you want to be able to identify the right method. Work out how you'd tell them apart manually, and write a query for it.Thelma
How do you determine that a ParameterInfo is generic?Marsha
@smartcaveman: Try ParameterInfo.ParameterType.IsGenericType.Thelma
Thanks... I realized that was a bit of a different question, so.. #4739326Marsha
C
2

You do it exactly the same way, but pass an instance of your object:

typeof (SomeObject).GetMethod(
       "SomeGenericInstanceMethod", 
        yourObject.GetType())  
                 // Or typeof(TheClass), 
                 // or typeof(T) if you're in a generic method
   .MakeGenericMethod(typeof(GenericParameter))

The MakeGenericMethod method only requires you to specify the generic type parameters, not the method's arguments.

You'd pass the arguments in later, when you call the method. However, at this point, they're passing as object, so it again doesn't matter.

Connivent answered 19/1, 2011 at 17:7 Comment(1)
Note that the GetMethod call may fail if yourObject is a subtype of the required one, as in my first example. The subtype may not satisfy the constraints - for example, consider Foo<T>(T item) where T : new() called as Foo<object>("hello"). We don't want to call Foo<string>("hello") as string doesn't have a parameterless constructor.Thelma

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