What does %prec '.' mean here in yacc?

Question

notype_declarator:
      notype_declarator '(' parmlist_or_identifiers  %prec '.'
        { $$ = build_nt (CALL_EXPR, $1, $3, NULL_TREE); }

Anyone familiar with yacc rules?

Crag

Answer 1

It declares that the construct has the same precedence as the '.' operator, which have been specified earlier.

Byelostok

Which symbol do you refer to by that construct? – Crag

The whole expression before the %prec, actually. It's telling yacc how to disambiguate that branch of the parse tree relative to other similar branches. – Byelostok

Answer 2

yacc program for showing error for 1) redeclaration of variable 2) Assignment expression error 3) operator missing

Dav