I got this err:
DbfError: unable to modify fields individually except in with or Process()
How to fix it?
This is my code:
with dbf.Table("aa.dbf") as table:
for record in table:
record[3] = 200
I got this err:
DbfError: unable to modify fields individually except in with or Process()
How to fix it?
This is my code:
with dbf.Table("aa.dbf") as table:
for record in table:
record[3] = 200
dbf
is different from most other DB packages in that instead of getting a completely seperate data structure (a bunch of rows as tuples, for example) you are working directly with the dbf file itself.
The problem I found myself running into was that when I would update multiple fields at once:
record.name = 'Some Name'
record.age = current_year -birth_year
record.hair_color = base_color * sun_tint
if an error happened any time after the first field I had a record that was only partially updated, and therefore no longer internally consistent.
To get around that problem I added code that it is kind of like commit on a per record basis, and the way to activate it is with with
or with Process
:
with record: # capture current values
record.field1 = something
record.field2 = something_else
record.field3 = another_thing
# now some other code
Now, if an error happens, the original values are restored; if no error happns, the new values are saved into the dbf
table on disk.
Besides with
on a record, you could also use Process
on a bunch of records, or you could avoid the issue and collect your data outside the record and then write it all at once:
for record in table:
new_data = {}
new_data['field1'] = 'a name'
new_data['field2'] = an_age
dbf.write(record, **new_data)
So, to get back to your code, the easiest way to fix it is probably:
with dbf.Table("aa.dbf") as table:
for record in dbf.Process(table):
record[3] = 200
dbf.write(record, **new_data)
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