What's the meaning of them and can I set them in different values?
Architectures are the ones you want to build, valid architectures are the ones you could conceive of building with your codebase.
So maybe you only want to build your binary for armv7s, but the same source code would compile fine for armv7 and armv6. So VALID_ARCHS = armv6 armv7 armv7s
, but you set ARCHS = armv7s
because that's all you actually want to build with your code.
Or, in Apple-ese:
ARCHS (Architectures)
Space-separated list of identifiers. Specifies the architectures (ABIs, processor models) to which the binary is targeted. When this build setting specifies more than one architecture, the generated binary may contain object code for each of the specified architectures.
and:
VALID_ARCHS (Valid Architectures)
Space-separated list of identifiers. Specifies the architectures for which the binary may be built. During the build, this list is intersected with the value of ARCHS build setting; the resulting list specifies the architectures the binary can run on. If the resulting architecture list is empty, the target generates no binary.
Source: Xcode Build Setting Reference
In practice, you leave VALID_ARCHS
alone and don't worry about changing it, and just fiddle with ARCHS
to set the architectures you want to build. Typically, you set a Debug build to just NATIVE_ARCH
, since you only want to build the debug version for the machine you'll be testing/running it on, and Release builds for the full spectrum of architectures you plan to support.
From Apple document,we know that the binary Xcode will build is the list Valid Architectures
intersected with Architectures
.
So ,i don't think Jeremy's answer is right, as he say:
So maybe you only want to build your binary for armv7s, but the same source code would
compile fine for armv7 and armv6. SoVALID_ARCHS = armv6 armv7 armv7s
, but you set ARCHS = armv7s because that's all you actually want to build with your code.
When you set VALID_ARCHS = armv6 armv7 armv7s
,and set ARCHS = armv7s
,the result of binary Xcode will build is armv7s,it could not compatible with armv6/armv7.
And if you want to compatible with armv6/armv7/armv7s,you must set VALID_ARCHS = armv6 armv7 armv7s
and ARCHS = armv6
.In this way , the result of binary Xcode will build is armv6, and it can run fine on both armv6/armv7/armv7s as arm processor is backwards compatible.
Pre xcode 12 era
VALID_ARCHS
could support such workflow:
- You set VALID_ARCHS on a target.
- When calling xcodebuild you pass the archs you want to build for with
xcodebuild ARCHS=...
to say which architectures you want to include in your binaries (they could be universal).
Xcode will take intersection of the two and build the targets for them. Imagine a target only supports arm64
, while most of your targets support x86_64
and arm64
. You call xcodebuild ARCHS="x86_64 arm64"
. This is what happens:
- You set on the target:
VALID_ARCHS=arm64
- xcodebuild sets
ARCHS
to:arm64
x86_64
- Target will be built for intersection
arm64
However, if you were to use ARCHS
, this is what happens
- You set on the target:
ARCHS=arm64
- xcodebuild overwrites
ARCHS
toarm64 x64
- Target will be built for
arm64
andx86_64
! <- not what you wanted.
xcode 12 era and beyond
https://developer.apple.com/documentation/xcode-release-notes/xcode-12-release-notes
VALID_ARCHS
is deprecated. Instead EXCLUDED_ARCHS
should be used on targets to exclude some architectures.
So now to do the same workflow, you set DISABLED_ARCHS=x86_64
on the aforementioned target.
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