String replaceAll not replacing i++;

Question

String preCode = "helloi++;world";
String newCode = preCode.replaceAll("i++;", "");

// Desired output :: newCode = "helloworld";

But this is not replacing i++ with blank.

Mockheroic

Answer 1

just use replace() instead of replaceAll()

String preCode = "helloi++;world";
String newCode = preCode.replace("i++;", "");

or if you want replaceAll(), apply following regex

String preCode = "helloi++;world";
String newCode = preCode.replaceAll("i\\+\\+;", "");

Note : in the case of replace() the first argument is a character sequence, but in the case of replaceAll the first argument is regex

Fallible

"this is helpfull if you have multiple occurances of character to be replaced" - The only difference between the two function is that one uses regex and the other uses string literals. Both their description starts with "Replaces each substring of this string that matches..." – Achromatism

java.util.regex.Pattern.quote(java.lang.String) will prevent you from making mistakes when converting a string literal to a regex. – Achromatism

thanks for the suggestion, i have updated the answer now – Fallible

Answer 2

try this one

 public class Practice {
 public static void main(String...args) {
 String preCode = "Helloi++;world";
 String newCode = preCode.replace(String.valueOf("i++;"),"");
 System.out.println(newCode);
}  
}

Pampero

What would you need String.valueOf("i++") for? Just using i++; should be sufficient. Also you are missing the semicolon. – Achromatism

Or you could do "i++;".toString(). – Shakhty

Answer 3

The problem is the string that you are using to replace , that is cnsidered as regex pattern to skip the meaning you will have to use escape sequence like below.

String newCode = preCode.replaceAll("i\\+\\+;", "");

Enhance