In a WPF application, when a user clicks on a button I want to open the Windows explorer to a certain directory, how do I do that?
I would expect something like this:
Windows.OpenExplorer("c:\test");
In a WPF application, when a user clicks on a button I want to open the Windows explorer to a certain directory, how do I do that?
I would expect something like this:
Windows.OpenExplorer("c:\test");
Why not Process.Start(@"c:\test");
?
Start(dir)
and Start("explorer.exe", dir)
is that the former will be smart enough to focus the existing window for dir
if there is one, while the latter opens a new window every time. –
Demagogy Process.Start("explorer.exe" , @"C:\Users");
I had to use this, the other way of just specifying the tgt dir would shut the explorer window when my application terminated.
Access denied
exception. –
Tolbert Process.Start(new ProcessStartInfo(your_path) { UseShellExecute = true })
if you wan't your code to stay cross plateform. It will use your machine default shell instead of trying to find the explorer.exe which doesn't exists and unix based OS. –
Timberlake UseShellExecute
default to true
anyway? –
Egbert This should work:
Process.Start(@"<directory goes here>")
Or if you'd like a method to run programs/open files and/or folders:
private void StartProcess(string path)
{
ProcessStartInfo StartInformation = new ProcessStartInfo();
StartInformation.FileName = path;
Process process = Process.Start(StartInformation);
process.EnableRaisingEvents = true;
}
And then call the method and in the parenthesis put either the directory of the file and/or folder there or the name of the application. Hope this helped!
process.EnableRaisingEvents = true;
, because process is null. –
Gorey EnableRaisingEvents
property, and only then Start
it? –
Egbert You can use System.Diagnostics.Process.Start
.
Or use the WinApi directly with something like the following, which will launch explorer.exe. You can use the fourth parameter to ShellExecute to give it a starting directory.
public partial class Window1 : Window
{
public Window1()
{
ShellExecute(IntPtr.Zero, "open", "explorer.exe", "", "", ShowCommands.SW_NORMAL);
InitializeComponent();
}
public enum ShowCommands : int
{
SW_HIDE = 0,
SW_SHOWNORMAL = 1,
SW_NORMAL = 1,
SW_SHOWMINIMIZED = 2,
SW_SHOWMAXIMIZED = 3,
SW_MAXIMIZE = 3,
SW_SHOWNOACTIVATE = 4,
SW_SHOW = 5,
SW_MINIMIZE = 6,
SW_SHOWMINNOACTIVE = 7,
SW_SHOWNA = 8,
SW_RESTORE = 9,
SW_SHOWDEFAULT = 10,
SW_FORCEMINIMIZE = 11,
SW_MAX = 11
}
[DllImport("shell32.dll")]
static extern IntPtr ShellExecute(
IntPtr hwnd,
string lpOperation,
string lpFile,
string lpParameters,
string lpDirectory,
ShowCommands nShowCmd);
}
The declarations come from the pinvoke.net website.
IDisposable
? –
Enchant Here's what worked for me:
Basically use the command line to call "start C:/path" And exit the terminal afterward, so "start c:/path && exit"
WindowsExplorerOpen(@"C:/path");
public static void WindowsExplorerOpen(string path)
{
CommandLine(path, $"start {path}");
}
private static void CommandLine(string workingDirectory, string Command)
{
ProcessStartInfo ProcessInfo;
Process Process;
ProcessInfo = new ProcessStartInfo("cmd.exe", "/K " + Command + " && exit");
ProcessInfo.WorkingDirectory = workingDirectory;
ProcessInfo.CreateNoWindow = true;
ProcessInfo.UseShellExecute = true;
ProcessInfo.WindowStyle = ProcessWindowStyle.Hidden;
Process = Process.Start(ProcessInfo);
Process.WaitForExit();
}
Neither of these worked for me:
Process.Start(@"c:\test");
Process.Start("explorer.exe" , @"C:\Users");
© 2022 - 2025 — McMap. All rights reserved.
Process.Start("calc.exe");
will run Calculator. You can pass it the full path to an executable and it will run it. – Unboned