I have a question about MPI_SENDRECV. here is an example:
PROGRAM sendrecv
IMPLICIT NONE
INCLUDE "mpif.h"
INTEGER a,b,myrank,nprocs,ierr
integer istat(MPI_STATUS_SIZE)
CALL MPI_INIT(ierr)
CALL MPI_COMM_SIZE(MPI_COMM_WORLD, nprocs, ierr)
CALL MPI_COMM_RANK(MPI_COMM_WORLD, myrank, ierr)
if (myrank.eq.0) then
a=1;b=3
else
a=2;b=4
endif
if (myrank == 0) then
call MPI_SENDRECV(b,1,MPI_REAL,1,0,
. a,1,MPI_REAL,1,0,
. MPI_COMM_WORLD,istat,ierr)
elseif (myrank == 1) then
call MPI_SENDRECV(b,1,MPI_REAL,0,0,
. a,1,MPI_REAL,0,0,
. MPI_COMM_WORLD,istat,ierr)
end if
if (myrank.eq.0) then
write(*,*) b,a
else
write(*,*) a,b
endif
CALL MPI_FINALIZE(ierr)
END
After this we get 3 4 and 3 4. My question is that is we replace the MPI_SENDRECV(if we assume that MPI_SENDRECV is send first and then receive)
if (myrank == 0) then
call MPI_SEND(b,1,MPI_REAL,1,0,MPI_COMM_WORLD,ierr)
call MPI_RECV(a,1,MPI_REAL,0,0,MPI_COMM_WORLD,istat,ierr)
elseif (myrank == 1) then
call MPI_SEND(b,1,MPI_REAL,0,0,MPI_COMM_WORLD,ierr)
call MPI_RECV(a,1,MPI_REAL,1,0,MPI_COMM_WORLD,istat,ierr)
end if
Then this will be deadlock So this means that MPI_SENDRECV it not first sends and then receives, but sends ans receives simultaneously,right?