How to modify memory contents using LLDB?

Question

What is the equivalent lldb command to the one shown below in GDB?

(gdb) set {char}0x02ae4=0x12

The values are arbitrary examples. With GDB I was able to easily edit the byte code at a given hex address while looking at dumps in terminal. Since I upgraded to mavericks I have been trying to fiddle around with lldb a little more but I am having a tough time in a few areas. Perhaps it doesn't even possess this functionality yet..

Mithridatism

Answer 1

According to lldb-basics guide LLDB alternative is memory write.

Also (lldb) help memory write defines such an input format:

memory write -i <filename> [-s <byte-size>] [-o <offset>] <address> <value> [<value> [...]]

   -f <format> ( --format <format> )
        Specify a format to be used for display.

   -i <filename> ( --infile <filename> )
        Write memory using the contents of a file.

   -o <offset> ( --offset <offset> )
        Start writng bytes from an offset within the input file.

   -s <byte-size> ( --size <byte-size> )
        The size in bytes to use when displaying with the selected format.

So, in Your case, something like (lldb) memory write 0x02ae4 0x12 should just work.

Duplicate

If you need to write more than one byte use the -s option: (lldb) memory write 0x02ae4 -s 2 0xFFFF – Ugh

Answer 2

memory write works, but you can also use the expression engine with a C expression like

p *(char*)0x2ae4 = 0x12

Nathalie

I assume this example should use 0x12 to be equivalent to the question's example. – French