Display pointer as array in Qt Creator with CDB for debugger

Question

Edit 2: If it's not possible, I will award the bounty to an answer that proves it (I mean provides some credible sources that back the claim that it's not possible).

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Let's say I have a pointer to an array, for example:

int arr[3];
int *p = new int[3];

I can see all the elements of arr, but only the first element of p. How can I see all 3 elements of p?

I tried the various suggestions from the answers from View Array contents in QtCreator and View Array contents in Qt Creator debugger, however they didn't work for me:

I assume this is because I'm on CDB, while the other 2 questions are for GDB. Is it possible to achieve the same for CDB?

Edit: I forgot to mention, but p,3 also doesn't work.

Narra

Try (int (&) [3])p – Labannah

@Labannah CDB logs this error: eERROR: Unable to add watch item "watch.1"/"(int (&) [3])p": Cannot add symbol '(int (&) [3])p': DEBUG_ANY_ID was returned as symbol index by AddSymbol. – Narra

Answer 1

Add into Expression Evaluator (menu Window->Views->Locals and Expressions)

(int(*)[3])p

That works fine in Qt Creator 3.2.1 Based on Qt 5.3.2 (GCC 4.9.2, 64 bit) Built on May 10 2016 at 17:53:15.

Madelenemadelin

Answer 2

You can use *(p+1) and *(p+2), to access the other two element.

Edit: @sashoalm You need to do this below:

int *pindex[3];
for(int j=0; j< 3;j++){
    pindex[j]= p+j;
}

Then you will be able to see all your p in the debugger.

Hope this helps.

Overhear

That's not a solution at all. I already know about p[1] and p[2]. I need it to work for arrays of hundreds of elements. – Narra

Answer 3

To see all element of *p:

1. Right Click On Local and Expressions.
2. enter *(p+1) and *(p+2).

So, You can see all three elements.

Pitsaw

If you're going to copy an existing answer you might pick one that hasn't been downvoted and doesn't answer the question satisfactorily. – Pilferage

Please don't copy others' answers, do some new contributions to SE – Vaccinia