I want to draw parallel line to given X,Y coordinate below code helps to draw ,
import numpy as np
import matplotlib.pyplot as plt
x = [187, 879, 722, 322]
y = [341, 344, 112, 112]
newX = []
newY = []
def findIntesection(p1x, p1y, p2x, p2y, p3x,p3y, p4x, p4y):
dx12 = p2x - p1x
dy12 = p2y - p1y
dx34 = p4x - p3x
dy34 = p4y - p3y
denominator = (dy12*dx34-dx12*dy34)
t1 = ((p1x - p3x) * dy34 + (p3y - p1y) * dx34)/ denominator
t2 = ((p3x - p1x) * dy12 + (p1y - p3y) * dx12)/ -denominator;
intersectX = p1x + dx12 * t1
intersectY = p1y + dy12 * t1
if (t1 < 0): t1 = 0
elif (t1 > 1): t1 = 1
if (t2 < 0): t2 = 0
elif (t2 > 1): t2 = 1
return intersectX,intersectY
def normalizeVec(x,y):
distance = np.sqrt(x*x+y*y)
return x/distance, y/distance
def getEnlarged(oldX, oldY, offset):
num_points = len(oldX)
for j in range(num_points):
i = j - 1
if i < 0:
i += num_points
k = (j + 1) % num_points
vec1X = oldX[j] - oldX[i]
vec1Y = oldY[j] - oldY[i]
v1normX, v1normY = normalizeVec(vec1X,vec1Y)
v1normX *= offset
v1normY *= offset
n1X = -v1normY
n1Y = v1normX
pij1X = oldX[i] + n1X
pij1Y = oldY[i] + n1Y
pij2X = oldX[j] + n1X
pij2Y = oldY[j] + n1Y
vec2X = oldX[k] - oldX[j]
vec2Y = oldY[k] - oldY[j]
v2normX, v2normY = normalizeVec(vec2X,vec2Y)
v2normX *= offset
v2normY *= offset
n2X = -v2normY
n2Y = v2normX
pjk1X = oldX[j] + n2X
pjk1Y = oldY[j] + n2Y
pjk2X = oldX[k] + n2X
pjk2Y = oldY[k] + n2Y
intersectX,intersetY = findIntesection(pij1X,pij1Y,pij2X,pij2Y,pjk1X,pjk1Y,pjk2X,pjk2Y)
#print(intersectX,intersetY)
newX.append(intersectX)
newY.append(intersetY)
getEnlarged(x, y, 20)
plt.plot(x, y)
plt.plot(newX, newY)
plt.show()
This gives result as below
Here it is giving good result by drawing parallel line to each line of our trapezoidal shaped , but i want it to be a closed shape in place of open shape i want to join the 1st and last coordinate so that it should form a closed shape. Any help will be appreciated .