How To Prevent WPF DataGrid From De-Selecting SelectedItem When Items Updated?
Asked Answered
L

4

9

My scenario: I have a background thread that polls for changes and periodically updates a WPF DataGrid's ObservableCollection (MVVM-style). The user can click on a row in the DataGrid and bring up the "details" of that row in an adjacent UserControl on the same main view.

When the background thread has updates, it cycles through the objects in the ObservableCollection and replaces individual objects if they have changed (in other words, I am not rebinding a whole new ObservableCollection to the DataGrid, but instead replacing individual items in the collection; this allows the DataGrid to maintain sorting order during updates).

The problem is that after a user has selected a specific row and the details are displayed in the adjacent UserControl, when the background thread updates the DataGrid the DataGrid loses the SelectedItem (it gets reset back to index of -1).

How can I retain the SelectedItem between updates to the ObservableCollection?

Lintel answered 2/9, 2010 at 15:45 Comment(0)
I
7

If your grid is single-selection, my suggestion is that you use the CollectionView as the ItemsSource instead of the actual ObservableCollection. Then, make sure that Datagrid.IsSynchronizedWithCurrentItem is set to true. Finally, at the end of your "replace item logic", just move the CollectionView's CurrentItem to the corresponding new item.

Below is a sample that demonstrates this. (I'm using a ListBox here though. Hope it works fine with your Datagrid).

EDIT - NEW SAMPLE USING MVVM:

XAML

<Window x:Class="ContextTest.MainWindow"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        x:Name="window"
        Title="MainWindow" Height="350" Width="525">
    <DockPanel>
        <ListBox x:Name="lb" DockPanel.Dock="Left" Width="200" 
                 ItemsSource="{Binding ModelCollectionView}"
                 SelectionMode="Single" IsSynchronizedWithCurrentItem="True">
            <ListBox.ItemTemplate>
                <DataTemplate>
                    <TextBlock Text="{Binding Path=Name}"/>
                </DataTemplate>
            </ListBox.ItemTemplate>
        </ListBox>

        <TextBlock Text="{Binding ElementName=lb, Path=SelectedItem.Description}"/>

    </DockPanel>
</Window>

Code-Behind:

using System;
using System.Windows;
using System.Windows.Data;
using System.Collections.ObjectModel;
using System.Windows.Threading;

namespace ContextTest
{
    /// <summary>
    /// Interaction logic for MainWindow.xaml
    /// </summary>
    public partial class MainWindow : Window
    {
        public MainWindow()
        {
            InitializeComponent();
            this.DataContext = new ViewModel();
        }
    }

    public class ViewModel
    {
        private DataGenerator dataGenerator;
        private ObservableCollection<Model> modelCollection;
        public ListCollectionView ModelCollectionView { get; private set; }

        public ViewModel()
        {
            modelCollection = new ObservableCollection<Model>();
            ModelCollectionView = new ListCollectionView(modelCollection);

            //Create models
            for (int i = 0; i < 20; i++)
                modelCollection.Add(new Model() { Name = "Model" + i.ToString(), 
                    Description = "Description for Model" + i.ToString() });

            this.dataGenerator = new DataGenerator(this);
        }

        public void Replace(Model oldModel, Model newModel)
        {
            int curIndex = ModelCollectionView.CurrentPosition;
            int n = modelCollection.IndexOf(oldModel);
            this.modelCollection[n] = newModel;
            ModelCollectionView.MoveCurrentToPosition(curIndex);
        }
    }

    public class Model
    {
        public string Name { get; set; }
        public string Description { get; set; }
    }

    public class DataGenerator
    {
        private ViewModel vm;
        private DispatcherTimer timer;
        int ctr = 0;

        public DataGenerator(ViewModel vm)
        {
            this.vm = vm;
            timer = new DispatcherTimer(TimeSpan.FromSeconds(5), 
                DispatcherPriority.Normal, OnTimerTick, Dispatcher.CurrentDispatcher);
        }

        public void OnTimerTick(object sender, EventArgs e)
        {
            Random r = new Random();

            //Update several Model items in the ViewModel
            int times = r.Next(vm.ModelCollectionView.Count - 1);
            for (int i = 0; i < times; i++)
            {   
                Model newModel = new Model() 
                    { 
                        Name = "NewModel" + ctr.ToString(),
                        Description = "Description for NewModel" + ctr.ToString()
                    };
                ctr++;

                //Replace a random item in VM with a new one.
                int n = r.Next(times);
                vm.Replace(vm.ModelCollectionView.GetItemAt(n) as Model, newModel);
            }
        }
    }
}

OLD SAMPLE:

XAML:

<Window x:Class="ContextTest.MainWindow"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        Title="MainWindow" Height="350" Width="525">
    <StackPanel>
        <ListBox x:Name="lb" SelectionMode="Single" IsSynchronizedWithCurrentItem="True" SelectionMode="Multiple">
            <ListBox.ItemTemplate>
                <DataTemplate>
                    <TextBlock Text="{Binding Path=Name}"/>
                </DataTemplate>
            </ListBox.ItemTemplate>
        </ListBox>

        <TextBlock Text="{Binding ElementName=lb, Path=SelectedItem.Name}"/>
        <Button Click="Button_Click">Replace</Button>


    </StackPanel>
</Window>

Code-behind:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;
using System.Collections.ObjectModel;
using System.ComponentModel;

namespace ContextTest
{
    /// <summary>
    /// Interaction logic for MainWindow.xaml
    /// </summary>
    public partial class MainWindow : Window
    {
        ObservableCollection<MyClass> items;
        ListCollectionView lcv;

        public MainWindow()
        {
            InitializeComponent();

            items = new ObservableCollection<MyClass>();
            lcv = (ListCollectionView)CollectionViewSource.GetDefaultView(items);
            this.lb.ItemsSource = lcv;
            items.Add(new MyClass() { Name = "A" });
            items.Add(new MyClass() { Name = "B" });
            items.Add(new MyClass() { Name = "C" });
            items.Add(new MyClass() { Name = "D" });
            items.Add(new MyClass() { Name = "E" });

        }

        public class MyClass
        {
            public string Name { get; set; }
        }

        int ctr = 0;
        private void Button_Click(object sender, RoutedEventArgs e)
        {
            MyClass selectedItem = this.lb.SelectedItem as MyClass;
            int index = this.items.IndexOf(selectedItem);
            this.items[index] = new MyClass() { Name = "NewItem" + ctr++.ToString() };
            lcv.MoveCurrentToPosition(index);
        }

    }
}
Iota answered 2/9, 2010 at 16:26 Comment(3)
Doesn't really work for me KarmicPuppet. Problem is I am doing MVVM and that makes it a slightly different problem. I can't just handle everything in a button click handler.Lintel
I'm not suggesting that you handle everything in a button click handler. That was just an example code. The idea is that you do something in your ViewModel that is similar to the one in the Button_Click event in my example. Let me try to write you an MVVM example. I'll get back to you.Iota
See Edit. I hope this gives you a better idea. It contains a ListBox whose data is being randomly updated every 5 seconds. You'll see that it still keeps the selection after the updates.Iota
C
3

I haven't worked with the WPF DataGrid, but I'd try this approach:

Add a property to the view-model that will hold the value of the currently selected item.

Bind SelectedItem to this new property using TwoWay.

This way, when the user selects a row, it will update the view-model, and when the ObservableCollection gets updated it won't affect the property to which SelectedItem is bound. Being bound, I wouldn't expect it could reset in the way you're seeing.

Codd answered 2/9, 2010 at 16:0 Comment(2)
That was my first thought Jay, but so far no dice. It's still resetting it.Lintel
@Chris Is the selected item itself being updated, or just other items?Codd
T
1

You could, in the logic that updates the Collection, save off the CollectionView.Current item reference to another variable. Then, after you're done updating, call CollectionView.MoveCurrentTo(variable) to reset the selected item.

Totalitarian answered 3/9, 2010 at 13:36 Comment(0)
K
0

Its probably resolved by now, but here is an example of what I did and it works for a grid of carts. I have a datagrid with ObservableCollection and CollectionView, populated from local variable containing carts:

        _cartsObservable = new ObservableCollection<FormOrderCart>(_formCarts);
        _cartsViewSource = new CollectionViewSource { Source = _cartsObservable };
        CartsGrid.ItemsSource = _cartsViewSource.View;

Later I change Valid prop of carts in a function - not directly, but important is that there is a change in item in ObservableCollection. To reflect the change and maintain selection I just refresh the CollectionViewSource (notice the inside View):

        var cart = _formCarts.ElementAt(index-1);
        cart.Valid = validity;
        _cartsViewSource.View.Refresh();

This way I am able to change the row color in grid to red if the cart is invalid, but also keep my selection.

EDIT: Spelling

Kippy answered 5/12, 2019 at 10:46 Comment(0)

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