How to Get User Group Names in Joomla 2.5
Asked Answered
R

4

9

I'm writing a Joomla 2.5 component that I had been developing in Joomla 1.7. I have been using code like this:

$user = JFactory::getUser();
$groups = $user->get('groups');

The $groups array would contain a list of ids with the group name as the index. Joomla 2.5 seems to have scrapped this functionality. I have been unable to find out how to get the group names without directly querying the database. Is there any method for getting a list of the groups a user is a member of without having to resort to querying the database?

Ramose answered 6/5, 2012 at 4:32 Comment(0)
T
8

The code I generated below gets the names of all the groups the user is a part of and stores them in the variable $groupNames separated by line breaks:

foreach ($user->groups as $groupId => $value){
    $db = JFactory::getDbo();
    $db->setQuery(
        'SELECT `title`' .
        ' FROM `#__usergroups`' .
        ' WHERE `id` = '. (int) $groupId
    );
    $groupNames .= $db->loadResult();
    $groupNames .= '<br/>';
}
print $groupNames;

It technically queries the database but is done via the Joomla API. This is working well for me on Joomla 2.5.

Turbid answered 10/11, 2012 at 19:17 Comment(1)
It is not good idea to execute any database queries in loops.Molar
T
4

Yes, this changed.

But what you should be using instead is:

JFactory::getUser()->getAuthorisedGroups();

or just getUserGroups

Tuberose answered 6/5, 2012 at 23:31 Comment(2)
For all of these cases, I have found that the returned array is of the form: ([0] => '1', [1] => '2'). They do not contain the group names.Ramose
Sadly they can't contain the name because it is not constrained to be unique.Elvinelvina
M
1

Real snippet:

            $user = JFactory::getUser();
            $db = JFactory::getDBO();

    $db->setQuery($db->getQuery(true)
        ->select('*')
        ->from("#__usergroups")
    );
    $groups=$db->loadRowList();

            $userGroups = $user->groups;
            $return=array();

          foreach ($groups as $key=>$g){
            if (array_key_exists($g[0],$userGroups)) array_push($return,$g[4]);
          }

          $groups=$return;

      /////printing groupnames for current user/////////////
         print_r($groups);
Myrick answered 22/11, 2012 at 20:53 Comment(7)
1. This answer is missing its educational explanation. 2. I don't understand why you wouldn't apply the filtration logic in the query; grabbing too much in the result set then cutting it down with php doesn't seem like professional-grade advice.Irenics
The fact that it works is only the start of posting a good answer that will help researchers. This answer still needs editing when you have time.Irenics
@mickmackusa, I agree that this is unoptimized in terms of database query, however, it is easier to debug when embedded in existing code regardless of the Joomla version. There are always few groups, but the table structure is different in different Joomla versions. Or does your task contain a large number of user groups that caused this discussion?Myrick
I do not need this solution personally. I am blowing my whistle that this answer is not using the most direct technique to generate the desired output. This is a free service that I provide which helps unknowing researchers to differentiate good answers from not-so-good answers because sometimes the vote tally tells lies.Irenics
@mickmackusa, Agree, but this is a pretty flexible answer for the reasons I mentioned earlier. This is not your case for help. But, thanks for such comments. They are really helpful.Myrick
You are already using $user->groups, just move the usage to the query. This improvement in no way diminishes the flexibility of your snippet. It only improves your snippet. Please edit your answer to optimize the filtration step at the earliest point and add an educational explanation as to how your advised code works and why you feel it is good advice. Refusing to do so will mean fewer researchers will be helped and/or researchers will be copy-pasting suboptimal code.Irenics
@mickmackusa, Not very clear. Can you show what you want with the source code (short version)?Myrick
E
0

Here it is:

<?php

    $user =& JFactory::getUser();

    foreach ($user->groups as $key => $value){
        echo $key.'<br>';
    }

?>

This will print all the user group names to the screen. The user group names are the "keys" of the array $user->groups.

Ethelynethene answered 11/9, 2012 at 13:15 Comment(1)
That prints the groups ids, not the names.Actinism

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