How do I check if a directory is a file or folder? [duplicate]
Asked Answered
M

1

1

Okay, so I'm using mingW, and the direct struct has no variables named d_type or stat, d_stat, or dd_stat. I need to know how I can use my direct struct to figure out if what I have is a file or folder. Here is my code.

#include <sys/types.h>
#include <sys/stat.h>
#include <dirent.h>
#include <errno.h>
#include <vector>
#include <string>
#include <iostream>

using namespace std;

/*function... might want it in some class?*/
int getdir (string dir, vector<string> &files)
{
    DIR *dp;
    struct stat _buf;
    struct dirent *dirp;
    if((dp  = opendir(dir.c_str())) == NULL) {
        cout << "Error(" << errno << ") opening " << dir << endl;
        return errno;
    }

    while ((dirp = readdir(dp)) != NULL) {

        if(stat(dirp->d_name, &_buf) != 0x4)
        files.push_back(string(dirp->d_name));
    }
    closedir(dp);
    return 0;
}

int main()
{
    string dir = string(".");
    vector<string> files = vector<string>();

    getdir(dir,files);

    for (unsigned int i = 0;i < files.size();i++) {
        cout << files[i] << endl;
    }
    return 0;
}
Moderation answered 2/10, 2010 at 5:48 Comment(2)
Note that stat() returns 0 on success and -1 on failure, and the zero value does not tell you whether it was a directory (the -1 tells you it wasn't).Dewhurst
Also, check out SO 3828192.Dewhurst
M
5

boost::filesystem::is_directory()

//I found it )  

//So, also you can try to call stat() function. ( on Windows ) 

(^_^)

Metasomatism answered 2/10, 2010 at 6:0 Comment(0)

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