Count number of emails in gmail using IMAP

Question

Can anyone tell me how I can get the number of unread items in my inbox from gmail using imap or something else and display it in a label in C# WinForms?

I tried using atom feeds, but never could get it

Here is what I want to look like, if it helps:

Eponym

Please remove the answer from the question and post it as an actual answer. Thanks! – Mcalpine

Answer 1

You probably want to find all messages with the UNSEEN flag set.

Imap imap = new Imap();
/* connect, login, etc. */
imap.Connect(...);
/* fill login and select folder code */

List<long> unseenList = imap.SearchFlag(Flag.Unseen);

// now you can get the count from unseeList
int unread = unseenList.Count;

Dantzler

Could you elaoborate a bit more im completly new to progrsmming – Eponym

Thanks for the help worked great so how would i show dis in a label – Eponym

Correct me if I'm wrong: you need to reference Mail.dll: lesnikowski.com/mail – Lindblad

Could you please tell me where you get this Imap class. Is there any .NET library available for Imap? – Airdry

Answer 2

SOLVED

Here is the code i used with the ImapX component:

 ImapX.ImapClient client = new ImapX.ImapClient("imap.gmail.com", 993, true);
        bool result = false;

        result = client.Connection();
        if (result)
            MessageBox.Show("Connection Established");

        result = client.LogIn(textBox1.Text, textBox2.Text);
        if (result)
        {
            MessageBox.Show("Logged in");
            ImapX.FolderCollection folders = client.Folders;
            ImapX.MessageCollection messages = client.Folders["INBOX"].Search("UNSEEN", true); //true - means all message parts will be received from server

            int unread = messages.Count;
            string unseen = unread.ToString();
            button1.Text = unseen;
        }

i just had to covert the int to a string and show the string (unseen) in the button. Thanks to quantumSoup for pointing me in the right direction

Eponym

If Url above did not work, it is possible to try to use new version from imapx.codeplex.com – Guenzi