Explode delimited string without creating empty elements [duplicate]

Question

$string = "|1|2|3|4|";
$array = explode("|", $string, -1); 

foreach ($array as $part) {
    echo $part."-";
}

I use -1 in explode to skip the last "|" in string. But how do I do if I also want to skip the first "|"?

Gamesome

Answer 1

You can use trim to Strip | from the beginning and end of a string and then can use the explode.

$string = "|1|2|3|4|";
$array = explode("|", trim($string,'|')); 

Haughay

Answer 2

preg_split(), and its PREG_SPLIT_NO_EMPTY option, should do just the trick, here.

And great advantage : it'll skip empty parts even in the middle of the string -- and not just at the beginning or end of it.

The following portion of code :

$string = "|1|2|3|4|";
$parts = preg_split('/\|/', $string, -1, PREG_SPLIT_NO_EMPTY);
var_dump($parts);

Will give you this resulting array :

array
  0 => string '1' (length=1)
  1 => string '2' (length=1)
  2 => string '3' (length=1)
  3 => string '4' (length=1)

Summerlin

Answer 3

take a substring first, then explode. http://codepad.org/4CLZqkle

<?php

$string = "|1|2|3|4|";
$string = substr($string,1,-1);
$array = explode("|", $string); 

foreach ($array as $part) {
    echo $part."-";
}
echo PHP_EOL ;

/* or use implode to join */
echo implode("-",$array);

?>

Axiom

Answer 4

You could use array_shift() to remove the first element from the array.

Rag