Adding custom action to UserModel's Admin page
Asked Answered
L

2

9

Is there any possibility to create custom action in admin page for django UserModel? I want automatize adding user to group (like adding him to staff, set some extra values, etc.), and of course create actions that take these changes back.

Thanks for your help.

Liponis answered 6/9, 2010 at 14:39 Comment(0)
C
16

Import User in your admin.py unregister it, create new ModelAdmin for it (or subclass the default one) and go wild.

It would look something like this I guess:

from django.contrib.auth.models import User

class UserAdmin(admin.ModelAdmin):
    actions = ['some_action']

    def some_action(self, request, queryset):
        #do something ...
    some_action.short_description = "blabla"

admin.site.unregister(User)
admin.site.register(User, UserAdmin)

Reference for actions.

Cinematography answered 6/9, 2010 at 14:44 Comment(1)
In addition, I guess you could also from django.contrib.auth.admin import UserAdmin and then subclass UserAdmin instead of ModelAdmin?Wingate
S
4

Working example without losing all default inline actions etc.
Here we will add action which activates selected users.

from django.contrib import admin
from django.contrib.auth.models import User
from django.contrib.auth.admin import UserAdmin


def make_active(modeladmin, news, queryset):
    queryset.update(is_active=True)
make_active.short_description = u"Activate selected Users"

class CustomUserAdmin(UserAdmin):
    actions = [make_active]


admin.site.unregister(User)
admin.site.register(User, CustomUserAdmin)
Shogunate answered 19/8, 2016 at 23:41 Comment(0)

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