How to remove/omit smaller contour lines using matplotlib
Asked Answered
H

2

9

I am trying to plot contour lines of pressure level. I am using a netCDF file which contain the higher resolution data (ranges from 3 km to 27 km). Due to higher resolution data set, I get lot of pressure values which are not required to be plotted (rather I don't mind omitting certain contour line of insignificant values). I have written some plotting script based on the examples given in this link http://matplotlib.org/basemap/users/examples.html.

After plotting the image looks like this

Contour Plot

From the image I have encircled the contours which are small and not required to be plotted. Also, I would like to plot all the contour lines smoother as mentioned in the above image. Overall I would like to get the contour image like this:-

Internet Image

Possible solution I think of are

  1. Find out the number of points required for plotting contour and mask/omit those lines if they are small in number.

or

  1. Find the area of the contour (as I want to omit only circled contour) and omit/mask those are smaller.

or

  1. Reduce the resolution (only contour) by increasing the distance to 50 km - 100 km.

I am able to successfully get the points using SO thread Python: find contour lines from matplotlib.pyplot.contour()

But I am not able to implement any of the suggested solution above using those points.

Any solution to implement the above suggested solution is really appreciated.

Edit:-

@ Andras Deak I used print 'diameter is ', diameter line just above del(level.get_paths()[kp]) line to check if the code filters out the required diameter. Here is the filterd messages when I set if diameter < 15000::

diameter is  9099.66295612
diameter is  13264.7838257
diameter is  445.574234531
diameter is  1618.74618114
diameter is  1512.58974168

However the resulting image does not have any effect. All look same as posed image above. I am pretty sure that I have saved the figure (after plotting the wind barbs).

Regarding the solution for reducing the resolution, plt.contour(x[::2,::2],y[::2,::2],mslp[::2,::2]) it works. I have to apply some filter to make the curve smooth.

Full working example code for removing lines:-

Here is the example code for your review

#!/usr/bin/env python
from netCDF4 import Dataset
import matplotlib
matplotlib.use('agg')
import matplotlib.pyplot as plt
import numpy as np
import scipy.ndimage
from mpl_toolkits.basemap import interp
from mpl_toolkits.basemap import Basemap


# Set default map
west_lon = 68
east_lon = 93
south_lat = 7
north_lat = 23

nc = Dataset('ncfile.nc')
# Get this variable for later calucation
temps = nc.variables['T2']
time = 0  # We will take only first interval for this example
# Draw basemap
m = Basemap(projection='merc', llcrnrlat=south_lat, urcrnrlat=north_lat,
                llcrnrlon=west_lon, urcrnrlon=east_lon, resolution='l')
m.drawcoastlines()
m.drawcountries(linewidth=1.0)
# This sets the standard grid point structure at full resolution
x, y = m(nc.variables['XLONG'][0], nc.variables['XLAT'][0])

# Set figure margins
width = 10
height = 8

plt.figure(figsize=(width, height))
plt.rc("figure.subplot", left=.001)
plt.rc("figure.subplot", right=.999)
plt.rc("figure.subplot", bottom=.001)
plt.rc("figure.subplot", top=.999)

plt.figure(figsize=(width, height), frameon=False)

# Convert Surface Pressure to Mean Sea Level Pressure
stemps = temps[time] + 6.5 * nc.variables['HGT'][time] / 1000.
mslp = nc.variables['PSFC'][time] * np.exp(9.81 / (287.0 * stemps) * nc.variables['HGT'][time]) * 0.01 + (
    6.7 * nc.variables['HGT'][time] / 1000)

# Contour only at 2 hpa interval
level = []
for i in range(mslp.min(), mslp.max(), 1):
    if i % 2 == 0:
        if i >= 1006 and i <= 1018:
            level.append(i)

# Save mslp values to upload to SO thread
# np.savetxt('mslp.txt', mslp, fmt='%.14f', delimiter=',')

P = plt.contour(x, y, mslp, V=2, colors='b', linewidths=2, levels=level)


# Solution suggested by Andras Deak
for level in P.collections:
    for kp,path in enumerate(level.get_paths()):
        # include test for "smallness" of your choice here:
        # I'm using a simple estimation for the diameter based on the
        #    x and y diameter...
        verts = path.vertices # (N,2)-shape array of contour line coordinates
        diameter = np.max(verts.max(axis=0) - verts.min(axis=0))

        if diameter < 15000: # threshold to be refined for your actual dimensions!
            #print 'diameter is ', diameter
            del(level.get_paths()[kp])  # no remove() for Path objects:(
            #level.remove() # This does not work. produces ValueError: list.remove(x): x not in list

plt.gcf().canvas.draw()


plt.savefig('dummy', bbox_inches='tight')
plt.close()

After the plot is saved I get the same image

Pic of working example

You can see that the lines are not removed yet. Here is the link to mslp array which we are trying to play with http://www.mediafire.com/download/7vi0mxqoe0y6pm9/mslp.txt

If you want x and y data which are being used in the above code, I can upload for your review.

Smooth line

You code to remove the smaller circles working perfectly. However the other question I have asked in the original post (smooth line) does not seems to work. I have used your code to slice the array to get minimal values and contoured it. I have used the following code to reduce the array size:-

slice = 15

CS = plt.contour(x[::slice,::slice],y[::slice,::slice],mslp[::slice,::slice], colors='b', linewidths=1, levels=levels)

The result is below.

irregular line

After searching for few hours I found this SO thread having simmilar issue:-

Regridding regular netcdf data

But none of the solution provided over there works.The questions similar to mine above does not have proper solutions. If this issue is solved then the code is perfect and complete.

Hussite answered 25/2, 2016 at 16:50 Comment(0)
Y
20

General idea

Your question seems to have 2 very different halves: one about omitting small contours, and another one about smoothing the contour lines. The latter is simpler, since I can't really think of anything else other than decreasing the resolution of your contour() call, just like you said.

As for removing a few contour lines, here's a solution which is based on directly removing contour lines individually. You have to loop over the collections of the object returned by contour(), and for each element check each Path, and delete the ones you don't need. Redrawing the figure's canvas will get rid of the unnecessary lines:

# dummy example based on matplotlib.pyplot.clabel example:
import matplotlib
import numpy as np
import matplotlib.cm as cm
import matplotlib.mlab as mlab
import matplotlib.pyplot as plt

delta = 0.025
x = np.arange(-3.0, 3.0, delta)
y = np.arange(-2.0, 2.0, delta)
X, Y = np.meshgrid(x, y)
Z1 = mlab.bivariate_normal(X, Y, 1.0, 1.0, 0.0, 0.0)
Z2 = mlab.bivariate_normal(X, Y, 1.5, 0.5, 1, 1)
# difference of Gaussians
Z = 10.0 * (Z2 - Z1)


plt.figure()
CS = plt.contour(X, Y, Z)

for level in CS.collections:
    for kp,path in reversed(list(enumerate(level.get_paths()))):
        # go in reversed order due to deletions!

        # include test for "smallness" of your choice here:
        # I'm using a simple estimation for the diameter based on the
        #    x and y diameter...
        verts = path.vertices # (N,2)-shape array of contour line coordinates
        diameter = np.max(verts.max(axis=0) - verts.min(axis=0))

        if diameter<1: # threshold to be refined for your actual dimensions!
            del(level.get_paths()[kp])  # no remove() for Path objects:(

# this might be necessary on interactive sessions: redraw figure
plt.gcf().canvas.draw()

Here's the original(left) and the removed version(right) for a diameter threshold of 1 (note the little piece of the 0 level at the top):

original for reference remove smaller than d=1

Note that the top little line is removed while the huge cyan one in the middle doesn't, even though both correspond to the same collections element i.e. the same contour level. If we didn't want to allow this, we could've called CS.collections[k].remove(), which would probably be a much safer way of doing the same thing (but it wouldn't allow us to differentiate between multiple lines corresponding to the same contour level).

To show that fiddling around with the cut-off diameter works as expected, here's the result for a threshold of 2:

result with threshold of 2

All in all it seems quite reasonable.


Your actual case

Since you've added your actual data, here's the application to your case. Note that you can directly generate the levels in a single line using np, which will almost give you the same result. The exact same can be achieved in 2 lines (generating an arange, then selecting those that fall between p1 and p2). Also, since you're setting levels in the call to contour, I believe the V=2 part of the function call has no effect.

import numpy as np
import matplotlib.pyplot as plt

# insert actual data here...
Z = np.loadtxt('mslp.txt',delimiter=',')
X,Y = np.meshgrid(np.linspace(0,300000,Z.shape[1]),np.linspace(0,200000,Z.shape[0]))
p1,p2 = 1006,1018

# this is almost the same as the original, although it will produce
# [p1, p1+2, ...] instead of `[Z.min()+n, Z.min()+n+2, ...]`
levels = np.arange(np.maximum(Z.min(),p1),np.minimum(Z.max(),p2),2)


#control
plt.figure()
CS = plt.contour(X, Y, Z, colors='b', linewidths=2, levels=levels)


#modified
plt.figure()
CS = plt.contour(X, Y, Z, colors='b', linewidths=2, levels=levels)

for level in CS.collections:
    for kp,path in reversed(list(enumerate(level.get_paths()))):
        # go in reversed order due to deletions!

        # include test for "smallness" of your choice here:
        # I'm using a simple estimation for the diameter based on the
        #    x and y diameter...
        verts = path.vertices # (N,2)-shape array of contour line coordinates
        diameter = np.max(verts.max(axis=0) - verts.min(axis=0))

        if diameter<15000: # threshold to be refined for your actual dimensions!
            del(level.get_paths()[kp])  # no remove() for Path objects:(

# this might be necessary on interactive sessions: redraw figure
plt.gcf().canvas.draw()
plt.show()

Results, original(left) vs new(right):

before after


Smoothing by resampling

I've decided to tackle the smoothing problem as well. All I could come up with is downsampling your original data, then upsampling again using griddata (interpolation). The downsampling part could also be done with interpolation, although the small-scale variation in your input data might make this problem ill-posed. So here's the crude version:

import scipy.interpolate as interp   #the new one

# assume you have X,Y,Z,levels defined as before

# start resampling stuff
dN = 10 # use every dN'th element of the gridded input data
my_slice = [slice(None,None,dN),slice(None,None,dN)]

# downsampled data
X2,Y2,Z2 = X[my_slice],Y[my_slice],Z[my_slice]
# same as X2 = X[::dN,::dN] etc.

# upsampling with griddata over original mesh
Zsmooth = interp.griddata(np.array([X2.ravel(),Y2.ravel()]).T,Z2.ravel(),(X,Y),method='cubic')

# plot
plt.figure()
CS = plt.contour(X, Y, Zsmooth, colors='b', linewidths=2, levels=levels)

You can freely play around with the grids used for interpolation, in this case I just used the original mesh, as it was at hand. You can also play around with different kinds of interpolation: the default 'linear' one will be faster, but less smooth.

Result after downsampling(left) and upsampling(right):

after downsample after upsample

Of course you should still apply the small-line-removal algorithm after this resampling business, and keep in mind that this heavily distorts your input data (since if it wasn't distorted, then it wouldn't be smooth). Also, note that due to the crude method used in the downsampling step, we introduce some missing values near the top/right edges of the region under consideraton. If this is a problem, you should consider doing the downsampling based on griddata as I've noted earlier.

Yelena answered 27/2, 2016 at 0:20 Comment(16)
I am able to figure out the smaller diameters with your code. However I am having trouble updating the figure. After using plt.gcf().canvas.draw() the saved fig looks same. I used this code P = plt.contour(x, y, mslp, V=2, colors='b', linewidths=2, levels=level) for plotting the image. How do I update the image which are saved as .png file? Also, you said that decreasing the resolution of your contour() and I have been trying to do this for past two days without success. Please show some code for reducing the resolution (it is to plotted on basemap) and I will accept the answer.Hussite
@Hussite this is probably a stupid question, but did you use savefig() after calling plt.gcf().canvas.draw()? I ran this whole thing in ipython, with an interactive Qt4Agg back-end. As for resolution: if your data are given on a mesh (I'm unfamiliar with basemap), you can just use a stride to make it less dense: plt.contour(x[::2,::2],y[::2,::2],mslp[::2,::2]) to throw out every other data point. If the data are scattered, perhaps you can use scipy.interpolate.griddata to interpolate over a not too dense mesh of your liking, and call contour for that.Azotize
Also: are you sure that it found a contour line to delete? Did you make it print a message when attempting to delete a contour line?Azotize
I have updated the question with your suggested solution. Have a look at.Hussite
@Hussite with sufficient downsampling your contour lines should become automatically smoother. Depending on the density of your data set, try using much less dense samples (so, say, using every 10th index rather than every 2nd, or 50th, you probably need a fairly sparse sample to get so smooth contour lines). As for the lack of deletion: it should work:( Could you try and add a minimal working example of what you're exactly doing? Just put in some sample data, you can even use the same as I used. I'm interested in the plotting/saving commands. And are you using an interactive shell?Azotize
I am not using interactive shell. But the full working code is posted above with the sample data I am working on for your review.Hussite
@Hussite there was a bug due to deleting indices in a for loop. I changed this to go backwards over the list of paths, and this seems to work great for your data. Please check if it works with your non-interactive code, and let me know if something's off. Note that I changed a few definitions, for instance I renamed level to levels at the beginning.Azotize
Awesome. Your code works and thanks. One last question. The smooth cure problem still exist. I am able to plot contour with less resolution but the required smoothness (cubic interpolation) does not seems to appear. I have tried to use the scipy.interpolate.griddata but never able to successfully implement it. The sample image after slicing the array is updated in the original post. Your help on this issue is highly appreciated.Hussite
@Hussite I've been thinking about the smoothing problem, and it's not really easy. Maybe it would be best to downsample the data (just like in your updated question), then resample on a denser grid using griddata. Anyway, this might be an altogether separate question, you should consider asking one as such.Azotize
I have accepted your answer. If you come across solution to the smooth problem please provide a link here. Thank you for giving me perfect answer.Hussite
@Hussite don't take this the wrong way, but I can see that with 40+ questions you've only ever voted 20 times. If you believe an answer is useful, please consider giving an upvote. I'm not talking about myself, I'm sure bunch of answers for your questions deserve upvotes.Azotize
Sorry it was my bad. Up voted your answer. I don't know how to give bounty to you for this answer. But I will ensure next time onward.Hussite
@Hussite a bounty is perfectly unnecessary:) Upvoting and accepting are the only things you should generally consider when asking, and only when it's merited. If an answer doesn't solve your problem: don't accept. If you don't find an answer useful: don't upvote. But otherwise, this is how you can help out those who help you:) Everybody wins.Azotize
@Hussite I've updated my answer with a smoothing attempt. I hope it'll help, it's far from perfect.Azotize
Thank you again for the answer. the solution provided is good enough for now.Hussite
Regarding "no remove() for Path objects", I think rather than using del(...) in the loop itself you can use the set_paths() method. I.e., level.set_paths([path for path in level.get_paths() if criteria_function(path)]).Incision
K
0

This is a pretty bad solution, but it's the only one that I've come up with. Use the get_contour_verts function in this solution you linked to, possibly with the matplotlib._cntr module so that nothing gets plotted initially. That gives you a list of contour lines, sections, vertices, etc. Then you have to go through that list and pop the contours you don't want. You could do this by calculating a minimum diameter, for example; if the max distance between points is less than some cutoff, throw it out.

That leaves you with a list of LineCollection objects. Now if you make a Figure and Axes instance, you can use Axes.add_collection to add all of the LineCollections in the list.

I checked this out really quick, but it seemed to work. I'll come back with a minimum working example if I get a chance. Hope it helps!


Edit: Here's an MWE of the basic idea. I wasn't familiar with plt._cntr.Cntr, so I ended up using plt.contour to get the initial contour object. As a result, you end up making two figures; you just have to close the first one. You can replace checkDiameter with whatever function works. I think you could turn the line segments into a Polygon and calculate areas, but you'd have to figure that out on your own. Let me know if you run into problems with this code, but it at least works for me.

import numpy as np
import matplotlib as mpl
import matplotlib.pyplot as plt

def checkDiameter(seg, tol=.3):
    # Function for screening line segments. NB: Not actually a proper diameter.
    diam = (seg[:,0].max() - seg[:,0].min(),
            seg[:,1].max() - seg[:,1].min())
    return not (diam[0] < tol or diam[1] < tol)

# Create testing data
x = np.linspace(-1,1, 21)
xx, yy = np.meshgrid(x,x)
z = np.exp(-(xx**2 + .5*yy**2))

# Original plot with plt.contour
fig0, ax0 = plt.subplots()
# Make sure this contour object actually has a tiny contour to remove
cntrObj = ax0.contour(xx,yy,z, levels=[.2,.4,.6,.8,.9,.95,.99,.999])

# Primary loop: Copy contours into a new LineCollection
lineNew = list()
for lineOriginal in cntrObj.collections:
    # Get properties of the original LineCollection
    segments = lineOriginal.get_segments()
    propDict = lineOriginal.properties()
    propDict = {key: value for (key,value) in propDict.items()
        if key in ['linewidth','color','linestyle']}  # Whatever parameters you want to carry over
    # Filter out the lines with small diameters
    segments = [seg for seg in segments if checkDiameter(seg)]
    # Create new LineCollection out of the OK segments
    if len(segments) > 0:
        lineNew.append(mpl.collections.LineCollection(segments, **propDict))

# Make new plot with only these line collections; display results
fig1, ax1 = plt.subplots()
ax1.set_xlim(ax0.get_xlim())
ax1.set_ylim(ax0.get_ylim())
for line in lineNew:
    ax1.add_collection(line)
plt.show()

FYI: The bit with propDict is just to automate bringing over some of the line properties from the original plot. You can't use the whole dictionary at once, though. First, it contains the old plot's line segments, but you can just swap those for the new ones. But second, it appears to contain a number of parameters that are in conflict with each other: multiple linewidths, facecolors, etc. The {key for key in propDict if I want key} workaround is my way to bypass that, but I'm sure someone else can do it more cleanly.

Kessler answered 26/2, 2016 at 5:0 Comment(1)
The idea looks promising. But little code of demonstration world be of great help.Hussite

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