How to increment / decrement hex color values with javascript / jQuery

Question

Is it possible to increment or decrement hex color values on a step-by-step basis in jQuery / javascript?

What I would like to do is something like this:

Adapting from a for-loop like

for (var i = 0; i <= 100; i++) {
    console.log(i);
}

I would like to do something like

for (var color = 000000; color <= ffffff; color++) {
    console.log(color);
}

without any conversion.

Is that possible? I've allready tried this:

for (var color = parseInt('000000', 16); color <= parseInt('ffffff', 16); color++){
    console.log(color.toString(16));
}

and it works but it's terribly slow (I get the warning that the script is slowing down the website and if I want to stop the script).

The reason why I want to do this: I would like to change the color stops of svg gradients in a certain interval. If I had for example this svg (simplified):

<svg>
    ...
    <linearGradient>
        <stop offset="0%"  stop-color="#C8E3EF"/>
        <stop offset="100%"  stop-color="#C8E3EF"/>
    </linearGradient>
    ...
</svg>

This gradient would of course appear as a solid color. Now I want to change it step by step to for example

<svg>
    ...
    <linearGradient>
        <stop offset="0%"  stop-color="#dfcf99"/>
        <stop offset="100%"  stop-color="#c5b6ec"/>
    </linearGradient>
    ...
</svg>

At each step or interval I want to go one value closer to the target color (through addition/substraction). In the end the result should be a smooth color-animation. Is that possible without the conversion? It does not have to be a for-loop btw., I just chose it to illustrate my idea.

Phalange

it's slow because you're looping 16,777,215 times. – Serilda

Yeah I know, but it should theoretically be an possible option to fade from black to white... – Phalange

Answer 1

I wrote a gradient-function some time ago, maybe it helps you (returns an Array):

function gradient(startColor, endColor, steps) {
             var start = {
                     'Hex'   : startColor,
                     'R'     : parseInt(startColor.slice(1,3), 16),
                     'G'     : parseInt(startColor.slice(3,5), 16),
                     'B'     : parseInt(startColor.slice(5,7), 16)
             }
             var end = {
                     'Hex'   : endColor,
                     'R'     : parseInt(endColor.slice(1,3), 16),
                     'G'     : parseInt(endColor.slice(3,5), 16),
                     'B'     : parseInt(endColor.slice(5,7), 16)
             }
             diffR = end['R'] - start['R'];
             diffG = end['G'] - start['G'];
             diffB = end['B'] - start['B'];

             stepsHex  = new Array();
             stepsR    = new Array();
             stepsG    = new Array();
             stepsB    = new Array();

             for(var i = 0; i <= steps; i++) {
                     stepsR[i] = start['R'] + ((diffR / steps) * i);
                     stepsG[i] = start['G'] + ((diffG / steps) * i);
                     stepsB[i] = start['B'] + ((diffB / steps) * i);
                     stepsHex[i] = '#' + Math.round(stepsR[i]).toString(16) + '' + Math.round(stepsG[i]).toString(16) + '' + Math.round(stepsB[i]).toString(16);
             }
             return stepsHex;

         }

Spirit

Nice! It doesn't answer my question, but it sure is helpfull :) – Phalange

Mate, I just had to comment to say that this function is amazing. Thanks so much! – Defeasible

Answer 2

Well you can do it simply by this way:

var incrementColor = function(color, step){
    var colorToInt = parseInt(color.substr(1), 16),                     // Convert HEX color to integer
        nstep = parseInt(step);                                         // Convert step to integer
    if(!isNaN(colorToInt) && !isNaN(nstep)){                            // Make sure that color has been converted to integer
        colorToInt += nstep;                                            // Increment integer with step
        var ncolor = colorToInt.toString(16);                           // Convert back integer to HEX
        ncolor = '#' + (new Array(7-ncolor.length).join(0)) + ncolor;   // Left pad "0" to make HEX look like a color
        if(/^#[0-9a-f]{6}$/i.test(ncolor)){                             // Make sure that HEX is a valid color
            return ncolor;
        }
    }
    return color;
};

For steps:

• 1 by 1 to 256 increment last color
• 256 by 256 increment middle color
• 65536 by 65536 increment first color

A running example here: http://jsfiddle.net/a3JbB/

Declare

Answer 3

Use setInterval to remove exception(stack overflow). jsfiddle

 var start = 0x000000,
    end = 0xFFFFFF, temp;
    var intervalId = setInterval(function(){
       if(start== end){clearInterval(intervalId )};
       temp = (start).toString(16);                  
             if(temp.length < 8){

                 temp = "0000000".substring(0, 8-temp.length)+temp; 
             } 
                       start++;
            console.log(temp ); 
     }, 10);   

Mechellemechlin

hmm, this kind of works, but seems to interrupt when i'm on the page. When I leave the page and get back to it (by changing tabs in firefox) I see the values being added to the console but then stop after a second or so. Is this intended? – Phalange

It will end after start reaches to end value if you want you can restart by resetting start. – Mechellemechlin