Printing lists in python without spaces

Question

I am doing a program that changes a number in base 10 to base 7, so i did this :

num = int(raw_input(""))
mod = int(0)
list = []
while num> 0:
    mod = num%7
    num = num/7
    list.append(mod)
list.reverse()
for i in range (0,len(list)):
    print list[i],

But if the number is 210 it prints 4 2 0 how do i get rid of the spaces

Butters

possible duplicate of How to convert list to string – Marinelli

Don't call your variable list, that shadows the builtin. Call it ll, l1, mylist or something else. – Swell

This is also a duplicate of Print all items in a list with a delimiter – Swell

Answer 1

You can use join with list comprehension:

>>> l=range(5)
>>> print l
[0, 1, 2, 3, 4]
>>> ''.join(str(i) for i in l)
'01234'

Also, don't use list as a variable name since it is a built-in function.

Marinelli

Hi thanks it worked fine but im new and i dont undestand how .join works can you give me a simple explanayion – Butters

@mariaalejandraescalante , it takes string as delimiter and concatenates elements in list with each other with delimiter between them. So this ','.join(['a', 'b', 'c']) will give 'a,b,c' – Arms

Answer 2

In Python 3 you can do:

print(*ll, sep='')

Where ll is a list of ints. Or for the OP's specific use-case:

print(*range(1,int(input())+1), sep='')

Your output will be like this if input = 4 :

1234

Goering

A more general answer is print(*ll, sep=''), where ll is a list of ints. – Swell

(This answer tries to do a one-liner on the OP's use-case but omits the base-8 check) – Swell

Answer 3

Convert the list to a string, and replace the white spaces.

strings = ['hello', 'world']

print strings

>>>['hello', 'world']

print str(strings).replace(" ", "")

>>>['hello','world']

Coheir

Answer 4

Take a look at sys.stdout. It's a file object, wrapping standard output. As every file it has write method, which takes string, and puts it directly to STDOUT. It also doesn't alter nor add any characters on it's own, so it's handy when you need to fully control your output.

>>> import sys
>>> for n in range(8):
...     sys.stdout.write(str(n))
01234567>>> 

Note two things

• you have to pass string to the function.
• you don't get newline after printing.

Also, it's handy to know that the construct you used:

for i in range (0,len(list)):
   print list[i],

is equivalent to (frankly a bit more efficient):

for i in list:
    print i,

Aland

Answer 5

Doing the following worked for me in Python3

print(*list,sep='')

Enviable

Answer 6

You can use below code snippet for python3

print(*list(range(1, n + 1)), sep='')

• * will remove initial and end character like [{}]
• sep = '' will remove the spaces between item.

Senhor

Answer 7

Use list_comprehension.

num= int(raw_input(""))
mod=int(0)
list =[]
while num> 0:
    mod=num%7
    num=num/7
    list.append(mod)
list.reverse()
print ''.join([str(list[i]) for i in range (0,len(list))])

Gupton

Hi thanks it worked fine but im new and i dont undestand how .join works can you give me a simple explanayion – Butters

Answer 8

The print() function has an argument to specify the end character which by default is '\n'. Specifying the end character as '' and printing using a loop will do what you are looking for:

n_list = [1,2,3,4,5]
for i in n_list:
    print(i, end='')

Athalla

Answer 9

s = "jay"
list = [ i for i in s ]

It you print list you will get:

['j','a','y']

new_s = "".join(list)

If you print new_s:

"jay"

Honeybunch