How to check if an integer is a perfect square [duplicate]

Question

How could I write an if-then statement that checks if an inputted integer is a perfect square or not (i.e. if I took the square root, it would be an integer as well: 4, 9, 16, 25, 36, etc.) in DrJava? Thank you!

Unreasonable

Answer 1

I am aware that this question already has an answer.... But just in case, this also works.

int x = (int) Math.sqrt(input);
if(Math.pow(x,2) == input)
    //Do stuff

Walther

Would the "int" before x and the "int" in the parentheses be my integer as well? – Unreasonable

no. Just replace yourIntHere. – Walther

Also, is there a way to negate that? As in saying if "int is not a perfect square." – Unreasonable

just add else block after if and add your code in that else block. – Walther

Awesome! Thank you so much you've been a big help!! :D – Unreasonable