is there a XNOR operator in javascript

Question

I'm new to js and I wonder if there is a XNOR operator in JS. I tried !(a^b) but it gives weird result. For example:

var a,b="aa"; 
a^b

this code returns true, however, I XNOR returns false.
UPDATE
I need to return true if the two operand are true(different from false values), or the two are false (both equals to : null, undefined,""-empty string- or 0)

Bicapsular

Isn't it just the equivalent of ==? – Islam

Have you considered using xor and not in chain? Also what is this var a,b="aa"; a^b? It looks completely wrong and doesn't give true at all. – Hyphenated

Same question in C# - hesitant to close as a dupe (hence why I undid my dupehammer vote) due to it being a different language. – Islam

Why are you trying to compare a string and an undefined value with bitwise operators?! – Temporal

Answer 1

Above is the truth table for XNOR. If A and B are both FALSE or TRUE, the resulting XNOR is true. Therefore, it seems to me as if simply checking for equality is actually the equivalent of XNOR.

So:

(a === b) = (a XNOR b)

EDIT: to work properly with your conditions: this should work:

a == b

Note that there are two "=", not three, indicating that this is comparing "truthy" values.

Nonchalant

@Bicapsular Then use !a === !b if you need to cast your values to proper booleans first – Temporal

I've updated my answer, try this: a == b (note that there are only two equal signs, not three). – Nonchalant

that's it @Temporal – Bicapsular

Answer 2

The bitwise xnor is:

~(a ^ b)

And the logical one;

a === b

Karlotte

Answer 3

try (a^b)==0 i think result of XNOR in javascript is: true^true = 0

Rhizome

Answer 4

Isn't it this simple?

!(A ^ B)

The inverse of XOR.

Maize

Answer 5

try this (!(A ^ B)) or this (A && B) || (!A && !B)

Shankle

Bitwise not is ~ – Hyphenated

yeah that what I'm using now, but I wonder if there is an operator that makes it simpler – Bicapsular