in c: func(void) vs. func() [duplicate]
Asked Answered
P

2

19

When a C function does not accept any arguments, does it have to be declared/defined with a "void" parameter by the language rules? PC-Lint seems to have problems when there's nothing at all in the argument-list, and I was wondering if it's something in the language syntax that I don't know about.

Edit: I just found a duplicate (back-dupe? it came first) question, C void arguments, which has more answers and explanations.

Pellucid answered 22/7, 2009 at 8:37 Comment(0)
C
37

void means the function does not take any parameters. For example,

int init (void)
{
    return 1;
}

This is not the same as defining

int init ()
{
    return 1;
}

because in the second case the compiler will not check whether the function is really called with no arguments at all; instead, a function call with arbitrary number of arguments will be accepted without any warnings (this is implemented only for the compatibility with the old-style function definition syntax, pre-ANSI).

Callboard answered 22/7, 2009 at 8:45 Comment(0)
R
7

IIRC func(void) in C will declare a function that takes no parameters whereas func() declares a function that will take any number of parameters. I believe the latter is an artifact coming from pre-ANSI C.

According to Wikipedia here, the declaration func() does basically declare the function "without information about the parameters".

Retrocede answered 22/7, 2009 at 8:40 Comment(3)
Isn't a function which takes any number of parameters defined as func(...) ?Pellucid
You believe correct, in K&R C parameter lists were defined different (and poorly). But in C++ f() is the same as f(void)Rasmussen
@Pellucid - a function of the form func(a, b, ...); declares a C function that takes a variable argument list so in a sense that would also take any number of parameters.Retrocede

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