How can I dump raw XML of my request and server's response using suds in python

Question

i'm using suds 0.4 and python 2.6, to communicate with remote server.

It's WSDL loads perfectly, but any function call returns error. Something is wrong with that server.

Now i need to get a dump of soap structure, that is sent to server and it's response, in pure soap either.

How can i do that?

Konstanz

Answer 1

Setting the logging for suds.transport to debug will get you the sent and received messages.

For an interactive session, I find this is good:

import logging
logging.basicConfig(level=logging.INFO)
logging.getLogger('suds.client').setLevel(logging.DEBUG)
logging.getLogger('suds.transport').setLevel(logging.DEBUG)
logging.getLogger('suds.xsd.schema').setLevel(logging.DEBUG)
logging.getLogger('suds.wsdl').setLevel(logging.DEBUG)

from suds.client import Client
s = Client('http://someservice?wsdl')

For specifically just the sent and received XML sent to a file, you'll need to play with the logging settings, see http://docs.python.org/library/logging.html

Softshoe