I'm setting the selection of my ngGrid from JavaScript, calling gridOptions.selectItem()
. I have multiSelect set to false, so there is only ever one row selected. I'd like the ngGrid to automatically scroll to show the newly selected row, but I don't know how to do this: can anyone help, please?
On a related topic: can I disable row selection by mouse click? If so, how?
Edited to add
I'd also like to disable keyboard navigation of the selected row, if possible.
What worked:
AardVark71's answer worked. I discovered that ngGrid defines a property ngGrid
on the gridOptions
variable which holds a reference to the grid object itself. The necessary functions are exposed via properties of this object:
$scope.gridOptions.selectItem(itemNumber, true);
$scope.gridOptions.ngGrid.$viewport.scrollTop(Math.max(0, (itemNumber - 6))*$scope.gridOptions.ngGrid.config.rowHeight);
My grid is fixed at 13 rows high, and my logic attempts to make the selected row appear in the middle of the grid.
I'd still like to disable mouse & keyboard changes to the selection, if possible.
What also worked:
This is probably closer to the 'Angular Way' and achieves the same end:
// This $watch scrolls the ngGrid to show a newly-selected row as close to the middle row as possible
$scope.$watch('gridOptions.ngGrid.config.selectedItems', function (newValue, oldValue, scope) {
if (newValue != oldValue && newValue.length > 0) {
var rowIndex = scope.gridOptions.ngGrid.data.indexOf(newValue[0]);
scope.gridOptions.ngGrid.$viewport.scrollTop(Math.max(0, (rowIndex - 6))*scope.gridOptions.ngGrid.config.rowHeight);
}
}, true);
although the effect when a row is selected by clicking on it can be a bit disconcerting.
ngGrid
property which is added to thegridOptions
property that holds a reference to the actual grid itself. The function call to scroll the viewport is then$scope.gridOptions.ngGrid.$viewport.scrollTop(rowNumber*$scope.gridOptions.ngGrid.config.rowHeight)
AardVark71 - Please update this to an Answer & I'll credit you: many thanks! – Adiathermancy