How to parse string into url.Values in golang?

Question

Let's suppose i have the following string

honeypot=&name=Zelalem+Mekonen&email=zola%40programmer.net&message=Hello+And+this+is+a+test+message...

and i want to convert it into url.Values struct and i have the following

data := url.Values{}

parameters := strings.Split(request.Body, "&")

for _, parameter := range parameters {

    parts := strings.Split(parameter, "=")

    data.Add(parts[0], parts[1])

}

which does convert it into url.Values but the problem is that it doesn't convert url encoded values like + into space, so first is there a better way to parse this? then if not how do i convert url encoded string to normal string first?

Thank's For Your Help...o

Animadversion

Answer 1

You could use url.ParseQuery to convert the raw query to url.Values with unescaping

package main

import (
    "fmt"
    "net/url"
)

func main() {
    t := "honeypot=&name=Zelalem+Mekonen&email=zola%40programmer.net&message=Hello+And+this+is+a+test+message..."
    v, err := url.ParseQuery(t)
    if err != nil {
        panic(err)
    }

    fmt.Println(v)
}

Result:

map[honeypot:[] name:[Zelalem Mekonen] email:[[email protected]] message:[Hello And this is a test message...]]

Tinker

Answer 2

You could first decode the URL with net/url/QueryUnescape.
It does converts '+' into '' (space).

Then you can start splitting the decoded string, or use net/url/#ParseRequestURI and get the URL.Query.

Duckbill

Answer 3

You can also use URL.Query:

package main

import (
   "fmt"
   "net/url"
)

func main() {
   get := url.URL{
      RawQuery: "honeypot=&name=Zelalem+Mekonen&email=zola%40programmer.net",
   }
   query := get.Query()
   // map[email:[[email protected]] honeypot:[] name:[Zelalem Mekonen]]
   fmt.Println(query)
}

https://golang.org/pkg/net/url#URL.Query

Febrifugal