I need to use an alternate glibc
version, newer than the one installed on my system (2.18
vs 2.15
). Several related issues are covered
here and here. The specific question I'm asking here is the following:
I set up the library path of the new dynamic linker (ld-2.18.so
) so that the new libc
(libc-2.18.so
) is found ahead of the old libc
(libc-2.15.so
). However, when I try to run a program with the new ld
, the old version of libc
is picked up, generating a SEGV
. Why is that happening?
Note: I know this can be fixed by using --rpath
at compile time or LD_LIBRARY_PATH
at run time. However, I would still like to understand why one of these is still needed.
The details follow:
I downloaded glibc-2.18
and built it at /opt/glibc-2.18
. By default, the file /opt/glibc-2.18/etc/ld.so.conf
is missing. I created it, and updated the library cache of the new glibc
as follows. I emphasize that: the new libc
is found before the old libc
:
$ cat /opt/glibc-2.18/etc/ld.so.conf
/opt/glibc-2.18/lib
/usr/local/lib
/lib/x86_64-linux-gnu
/usr/lib/x86_64-linux-gnu
/usr/lib/x86_64-linux-gnu/mesa
/lib
/usr/lib
$ /opt/glibc-2.18/sbin/ldconfig -v |& grep -E '^[^'$'\t'']|libc\.'
/opt/glibc-2.18/sbin/ldconfig: Path `/opt/glibc-2.18/lib' given more than once
/opt/glibc-2.18/sbin/ldconfig: Can't stat /opt/glibc-2.18/lib64: No such file or directory
/opt/glibc-2.18/sbin/ldconfig: Can't stat /opt/glibc-2.18/libx32: No such file or directory
/opt/glibc-2.18/lib:
libc.so.6 -> libc-2.18.so
/usr/local/lib:
/lib/x86_64-linux-gnu:
libc.so.6 -> libc-2.15.so
/usr/lib/x86_64-linux-gnu:
/usr/lib/x86_64-linux-gnu/mesa:
/lib:
/usr/lib:
Then, I created a simple C program:
$ cat <<EOF >a.c
> #include <stdio.h>
> int main()
> {
> fprintf(stdout, "ok\n");
> return 0;
> }
> EOF
$ g++ a.c
$ file a.out
a.out: ELF 64-bit LSB executable, x86-64, version 1 (SYSV), dynamically linked (uses shared libs), for GNU/Linux 2.6.24, BuildID[sha1]=0x43b8484e3910072375d68418cb6327478266c0e9, not stripped
$ ldd a.out
linux-vdso.so.1 => (0x00007fffd7ffe000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007fa7c47bd000)
/lib64/ld-linux-x86-64.so.2 (0x00007fa7c4b9b000)
$ readelf -a a.out | grep lib
[Requesting program interpreter: /lib64/ld-linux-x86-64.so.2]
0x0000000000000001 (NEEDED) Shared library: [libc.so.6]
000000601000 000100000007 R_X86_64_JUMP_SLO 0000000000000000 __libc_start_main + 0
1: 0000000000000000 0 FUNC GLOBAL DEFAULT UND __libc_start_main@GLIBC_2.2.5 (2)
46: 00000000004005f0 2 FUNC GLOBAL DEFAULT 13 __libc_csu_fini
52: 0000000000000000 0 FUNC GLOBAL DEFAULT UND __libc_start_main@@GLIBC_
57: 0000000000400560 137 FUNC GLOBAL DEFAULT 13 __libc_csu_init
000000: Version: 1 File: libc.so.6 Cnt: 1
$ objdump -x a.out | grep -A3 Version
Version References:
required from libc.so.6:
0x09691a75 0x00 02 GLIBC_2.2.5
As seen above, this program has the old ld
hard-coded inside. I can forcefully run it with the new ld
, and I expect the path of the new ld
to be used (you can see the new ld.so.cache
being opened). However, for some reason I'm trying to understand, the old libc
is found before the new libc
, generating a SEGV:
$ /opt/glibc-2.18/lib/ld-2.18.so ./a.out
Segmentation fault (core dumped)
$ strace /opt/glibc-2.18/lib/ld-2.18.so ./a.out |& grep open
open("./a.out", O_RDONLY|O_CLOEXEC) = 3
open("/opt/glibc-2.18/etc/ld.so.cache", O_RDONLY|O_CLOEXEC) = 3
open("/lib/x86_64-linux-gnu/libc.so.6", O_RDONLY|O_CLOEXEC) = 3
I can also compile with the new library and bake-in the new ld
as follows:
$ g++ -L/opt/glibc-2.18/lib -Wl,--dynamic-linker=/opt/glibc-2.18/lib/ld-2.18.so a.c -o a.2.18.out
$ file a.2.18.out
a.2.18.out: ELF 64-bit LSB executable, x86-64, version 1 (SYSV), dynamically linked (uses shared libs), for GNU/Linux 2.6.24, BuildID[sha1]=0x25ab43f3d29b49fa21385a15e43325e9fb904e81, not stripped
$ ldd a.2.18.out
linux-vdso.so.1 => (0x00007fffa68da000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007f9df5cbe000)
/opt/glibc-2.18/lib/ld-2.18.so => /lib64/ld-linux-x86-64.so.2 (0x00007f9df609c000)
$ readelf -a a.2.18.out | grep lib
[Requesting program interpreter: /opt/glibc-2.18/lib/ld-2.18.so]
0x0000000000000001 (NEEDED) Shared library: [libc.so.6]
000000601000 000100000007 R_X86_64_JUMP_SLO 0000000000000000 __libc_start_main + 0
1: 0000000000000000 0 FUNC GLOBAL DEFAULT UND __libc_start_main@GLIBC_2.2.5 (2)
54: 0000000000400600 2 FUNC GLOBAL DEFAULT 13 __libc_csu_fini
60: 0000000000000000 0 FUNC GLOBAL DEFAULT UND __libc_start_main@@GLIBC_
65: 0000000000400570 137 FUNC GLOBAL DEFAULT 13 __libc_csu_init
000000: Version: 1 File: libc.so.6 Cnt: 1
$ objdump -x a.2.18.out | grep -A3 Version
Version References:
required from libc.so.6:
0x09691a75 0x00 02 GLIBC_2.2.5
Still, if I try to run the new program the same thing happens, the old libc
is being used instead of the new libc
:
$ ./a.2.18.out
Segmentation fault (core dumped)
$ strace ./a.2.18.out |& grep open
open("/opt/glibc-2.18/etc/ld.so.cache", O_RDONLY|O_CLOEXEC) = 3
open("/lib/x86_64-linux-gnu/libc.so.6", O_RDONLY|O_CLOEXEC) = 3
With either executable, specifying LD_LIBRARY_PATH=/opt/glibc-2.18/lib
makes it work. However, my question here is why that is still needed, given that the path of the new ld
is configured at the beginning to pick up the new libc
ahead of the old libc
.