Reading File from Uri gives java.io.FileNotFoundException: open failed: ENOENT

When picking an image using an ACTION_GET_CONTENT intent, I get a URI that I can't open the file from. If I try to open the file, like this:

InputStream in = new FileInputStream(new File(uri.getPath()));

It gives the following exception:

03-11 15:14:36.132  20557-20557/my.package W/System.err﹕ java.io.FileNotFoundException: /document/image:9537: open failed: ENOENT (No such file or directory)
03-11 15:14:36.138  20557-20557/my.package W/System.err﹕ at libcore.io.IoBridge.open(IoBridge.java:456)
03-11 15:14:36.138  20557-20557/my.package W/System.err﹕ at java.io.FileInputStream.<init>(FileInputStream.java:76)

/document/image:9537 seems to indeed be an incorrect path, but how do I get the correct path?

I use this logic to open the image picker:

Intent photoPickerIntent = new Intent(Intent.ACTION_GET_CONTENT);
photoPickerIntent.setType("image/*");
photoPickerIntent.putExtra("return-data", false);
startActivityForResult(Intent.createChooser(photoPickerIntent, "Complete action using"), PICK_FROM_FILE);

And retrieve the Uri in the onActivityResult like this:

public void onActivityResult(int requestCode, int resultCode, Intent data)
{
    ....
    Uri uri = data.getData();

I need to get the file to do decoding to make it smaller.

If I try to open the file, like this:

That will not work for most modern Android devices. Most likely, you received a content: Uri. This is fairly normal on newer versions of Android. Future versions of Android might block file: Uri values.

I need to get the file to do decoding to make it smaller.

There does not have to be a file associated with a given Uri. That Uri might point to:

A local file on external storage
A local file on internal storage for the other app
A local file on removable storage
A local file that is encrypted and needs to be decrypted on the fly
A stream of bytes held in a BLOB column in a database
A piece of content that needs to be downloaded by the other app first
...and so on

Use a ContentResolver and openInputStream() to get an InputStream on the content pointed to by the Uri. Then, pass that to your decoding logic, such as BitmapFactory and its decodeStream() method.

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