RestTemplate.exchange() does not encode '+'?
Asked Answered
C

1

6

The RestTemplate.exchange() will encode all the invalid characters in URL but not + as + is a valid URL character. But how to pass a + in any URL's query parameter?

Comprador answered 3/8, 2018 at 15:41 Comment(0)
C
15

If the URI you pass to the RestTemplate has encoded set as true then it will not perform the encoding on the URI you pass else it will do.

import java.io.UnsupportedEncodingException;
import java.net.URI;
import java.net.URLEncoder;
import java.util.Collections;
import org.springframework.http.HttpEntity;
import org.springframework.http.HttpHeaders;
import org.springframework.http.HttpMethod;
import org.springframework.http.ResponseEntity;
import org.springframework.http.client.BufferingClientHttpRequestFactory;
import org.springframework.http.client.SimpleClientHttpRequestFactory;
import org.springframework.web.client.RestTemplate;
import org.springframework.web.util.UriComponentsBuilder;

class Scratch {

  public static void main(String[] args) {

    RestTemplate rest = new RestTemplate(
        new BufferingClientHttpRequestFactory(new SimpleClientHttpRequestFactory()));

    HttpHeaders headers = new HttpHeaders();
    headers.add("Content-Type", "application/json");
    headers.add("Accept", "application/json");
    HttpEntity<String> requestEntity = new HttpEntity<>(headers);

    UriComponentsBuilder builder = null;
    try {
      builder = UriComponentsBuilder.fromUriString("http://example.com/endpoint")
          .queryParam("param1", URLEncoder.encode("abc+123=", "UTF-8"));
    } catch (UnsupportedEncodingException e) {
      e.printStackTrace();
    }

    URI uri = builder.build(true).toUri();
    ResponseEntity responseEntity = rest.exchange(uri, HttpMethod.GET, requestEntity, String.class);
  }

}

So if you need to pass a query param with + in it then the RestTemplate will not encode the + but every other invalid URL character as + is a valid URL character. Hence you have to first encode the param (URLEncoder.encode("abc+123=", "UTF-8")) and then pass the encoded param to RestTemplate stating that the URI is already encoded using builder.build(true).toUri();, where true tells the RestTemplate that the URI is alrady encoded so not to encode again and hence the + will be passed as %2B.

  1. With builder.build(true).toUri(); OUTPUT : http://example.com/endpoint?param1=abc%2B123%3D as the encoding will be perfromed once.
  2. With builder.build().toUri(); OUTPUT : http://example.com/endpoint?param1=abc%252B123%253D as the encoding will be perfromed twice.
Comprador answered 3/8, 2018 at 18:26 Comment(3)
I was having a same problem, and your answer helped me to solve my issue.Larimor
Glat it helped you.Comprador
What if the issue is not the URI, but in one of the uriVariables. Like url = "https://server/api?param={param}"; paramValue = "1+2"; restTemplate.exchange(url,GET,req,data.class,paramValue). This seems to have the same issue. Is manually building the URI the only workaround?Humblebee

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