Printing a sequence from a fasta file
Asked Answered
P

5

5

I often need to find a particular sequence in a fasta file and print it. For those who don't know, fasta is a text file format for biological sequences (DNA, proteins, etc.). It's pretty simple, you have a line with the sequence name preceded by a '>' and then all the lines following until the next '>' are the sequence itself. For example:

>sequence1
ACTGACTGACTGACTG
>sequence2
ACTGACTGACTGACTG
ACTGACTGACTGACTG
>sequence3
ACTGACTGACTGACTG

The way I'm currently getting the sequence I need is to use grep with -A, so I'll do

grep -A 10 sequence_name filename.fa

and then if I don't see the start of the next sequence in the file, I'll change the 10 to 20 and repeat until I'm sure I'm getting the whole sequence.

It seems like there should be a better way to do this. For example, can I ask it to print up until the next '>' character?

Popper answered 1/10, 2014 at 15:17 Comment(0)
S
9

Using the > as the record separator:

awk -v seq="sequence2" -v RS='>' '$1 == seq {print RS $0}' file
>sequence2
ACTGACTGACTGACTG
ACTGACTGACTGACTG
Stheno answered 1/10, 2014 at 15:39 Comment(2)
+1 Nice. I presume you know you can save yourself the -v if you put RS='>' AFTER the script but before the file...Esther
I do but I like to keep the variables up front and the files at the end (much like a BEGIN block can appear anywhere in the script, but is usually seen at the beginning).Stheno
E
2

Like this maybe:

awk '/>sequence1/{p++;print;next} /^>/{p=0} p' file

So, if the line starts with >sequence1, set a flag (p) to start printing, print this line and move to next. On subsequent lines, if the line starts with >, change p flag to stop printing. In general, print if the flag p is set.

Or, improving a little on your grep solution, use this to cut off the -A (after) context:

grep -A 999999 "sequence1" file | awk 'NR>1 && /^>/{exit} 1'

So, that prints up to 999999 lines after sequence1 and pipes them into awk. Awk then looks for a > at the start of any line after line 1, and exits if it finds one. Until then, the 1 causes awk to do its standard thing, which is print the current line.

Esther answered 1/10, 2014 at 15:24 Comment(0)
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1

Using sed only:

sed -n '/>sequence3/,/>/ p' | sed '${/>/d}'
Skelton answered 1/10, 2014 at 20:47 Comment(0)
A
0
$ perl -0076 -lane 'print join("\n",@F) if $F[0]=~/sequence2/' file
Alphaalphabet answered 1/10, 2014 at 16:48 Comment(0)
T
0

This question has excellent answers already. However, if you are dealing with FASTA records often, I would highly recommend Python's Biopython Module. It has many options and make life easier if you want to manipulate FASTA records. Here is how you can read and print the records:

from Bio import SeqIO
import textwrap

for seq_record in SeqIO.parse("input.fasta", "fasta"):
    print(f'>{seq_record.id}\n{seq_record.seq}')

#If you want to wrap the record into multiline FASTA format
#You can use textwrap module
for seq_record in SeqIO.parse("input.fasta", "fasta"):
    dna_sequence = str(seq_record.seq)
    wrapped_dna_sequence = textwrap.fill(dna_sequence, width=8)
    print(f'>{seq_record.id}\n{wrapped_dna_sequence}')
Tressa answered 3/2, 2023 at 23:54 Comment(0)

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